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cestrela7 [59]
3 years ago
11

Lithium-6 has a mass of 6.0151 amu and lithium-7 has a mass of 7.0160 amu. The relative abundance of Li-6 is 7.42% and the relat

ive abundance of Li-7 is 92.58%. Based on this data alone, calculate the average atomic mass for lithium to the correct number of significant digits.
Chemistry
2 answers:
horsena [70]3 years ago
3 0
Average atomic mass is the weighted average atomic masses with regard to the relative abundance of the isotopes 
average atomic mass of Li = relative abundance of Li-6 x mass of Li-6 + relative abundance of Li-7 x mass of Li-7
average atomic mass of Li = (7.42% x 6.0151 a.m.u) + (92.58% x 7.0160 a.m.u)
                                           = 0.446 + 6.495
                                           = 6.941 amu
average atomic mass of Li is 6.941 amu
Bezzdna [24]3 years ago
3 0

Answer: The average atomic mass of Lithium is 6.94 amu.

Explanation:

Mass of isotope Li-6 = 6.0151 amu

% abundance of isotope  Li-6 = 7.42%= \frac{7.42}{100}=0.0742

Mass of isotope Li-7=  7.0160

% abundance of isotope Li-7 = 92.58% = \frac{92.58}{100}=0.9258

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(6.0151\times 0.0742)+(7.0160\times 0.9258)]

A=6.94

Therefore, the average atomic mass of Lithium is 6.94 amu.

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Based on the name, which substance is a covalent compound?
Sindrei [870]

Answer:

dinitrogen pentoxide

Explanation:

Based on the research, dinitrogen pentoxide is a chemical compound containing only nitrogen and oxygen which is both nonmetal. When two nonmetals or two negatively charged atoms try to form bonds, they always form covalent bonds. Hence, Dinitrogen Pentoxide is not ionic - it is covalent.

3 0
3 years ago
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4 0
3 years ago
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Calculate the change in ph when 3.00 ml of 0.100 m hcl(aq) is added to 100.0 ml of a buffer solution that is 0.100 m in nh3(aq)
nikklg [1K]

The change in pH is calculated by:

pOH = Protein kinase B + log [NH4+]/ [NH3] 

Protein kinase B of ammonia = 4.74 

initial potential of oxygen hydroxide= 4.74 + log 0.100/0.100 = 4.74 
pH = 14 - 4.74=9.26 

moles NH4+ = moles NH3 = 0.100 L x 0.100 M = 0.0100 
moles H+ added = 3.00 x 10^-3 L x 0.100 M=0.000300 

NH3 + H+ = NH4+ 
moles NH3 = 0.0100 - 0.000300=0.00970 
moles NH4+ = 0.0100 + 0.000300=0.0103 

pOH = 4.74 + log 0.0103/ 0.00970= 4.77 
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the change is  = 9.26 - 9.23 =0.03 

7 0
3 years ago
A 25.00-g sample of a solid is placed in a graduated cylinder, and then the cylinder is filled to the 50.0-mL mark with benzene.
aliina [53]

Answer:

solid density = 3.85 g/mL

Explanation:

First we calculate the mass of the benzene:

benzene mass = 63.29 - 25 = 38.29 g

We know that density = mass / volume

So the volume of benzene will be:

volume = mass / density

volume = 38.29 / 0.880 = 43.51 cm³ =  43.51 mL of benzene     (1 cm³ = 1 mL)

Now the volume of the sample will be:

sample volume = 50 - 43.51 = 6.49 mL

Now we can calculate the density of the solid:

density = mass / volume

solid density = 25 / 6.49 = 3.85 g/mL

7 0
3 years ago
A meteorological balloon contains 250.0 l he at 22°c and 740.0mmhg if the volume of the balloon can vary according to external c
Over [174]

Answer:

243.15 l

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁ where P₁, V₁ and T₁ are the initial pressure, volume and temperature of the meteorological balloon and  P₂, V₂ and T₂ are the initial pressure, volume and temperature of the meteorological balloon.

P₁ = 740 mmHg V₁ = 250 l and T₁ = 22°C + 273 = 295 K,

P₂ =  0.750 atm = 0.750 × 760 mmHg = 570 mmHg (since 1 atm = 760 mmHg) and T₂ = -52°C + 273 = 221 K  

V₂ = P₁V₁T₂/P₂T₁ = 740 mmHg × 250 l × 221 K/570 mmHg × 295 K = 243.15 l

V₂ = 243.15 l

So the volume it would occupy at an altitude of temperature -52 °C where it pressure is 0.750 atm  is 243.15 l

4 0
4 years ago
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