Answer:
0.316 moles are produced.
Explanation:
We state the redox reaction:
4HNO₃ + Cu → Cu(NO₃)₂ + 2NO₂ + 2H₂O
We need to determine the limting reactant:
0.1 L . 14 M = 1.4 moles
10 g . 1mol/ 63.54g =0.158 mol
Cu is the limiting reactant. Let's see
4 moles of acid need 1 mol of Cu to react
1.4 moles of acid may react to (4 . 1) / 1.4 = 0.35 moles
We do not have enough Cu.
1 mol of Cu can produce 1 mol of NO₂
Then 0.158 moles will produce, 0.316 moles. (double of moles)
If we see stoichiometry, ratio is 1:2
Answer:
Explanation:
Hello!
In this case, according to the ideal gas equation ratio for two states:
Whereas both n and R are cancelled out as they don't change, we obtain:
Thus, by solving for the final pressure, we obtain:
Now, since initial conditions are 1.00 atm, 273.15 K and 17 L and final temperature and volume are 94 + 273 = 367 K and 12 L respectively, the resulting pressure turns out to be:
Best regards!
Answer:
option c
Explanation:
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The volume measured using such a cylinder will be reported to the nearest 10th mL.
<h3>Cylinder graduation</h3>
10 mL graduated cylinders are always read to the nearest two decimal places.
100 mL graduated cylinders are always read to the nearest 1 decimal place. The nearest 1 decimal place is the same thing as the nearest 10th.
Thus, a reading made using a 100mL increment graduated cylinder would be reported to the nearest 10th mL.
More on cylinder graduation can be found here: brainly.com/question/14427988
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