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3 years ago

What is ionization constant of an acid?

Chemistry

1 answer:

egoroff_w [7]3 years ago

4 0

Answer:

ionization constant of an acid (Ka) is the equilibrium constant for the ionization of an acid.

Explanation:

The acid ionization represents the fraction of the original acid that has been ionized in solution. Therefore, the numerical value of Ka is a reflection of the strength of the acid.

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True or False? In a C++ floating-point constant, a decimal point is not required if exponential (E) notation is used.

defon

Answer:

The answer is True

Explanation:

This is because they are equivalent and have same number of bit.

7 0

3 years ago

Nicotine, a component of tobacco, is composed of c, h, and n. a 4.725 −mg sample of nicotine was combusted, producing 12.818 mg

ehidna [41]

C = 12.818 mg CO2 (1 mmol CO2/44 mg CO2) (1 mmol C/1 mmol CO2) = 0.29 mmol

H = 3.675 mg of H2O (1 mmol H2O/18 mg H2O) (2 mmol H/1 mmol H2O) = 0.41 mmol

N = (4.725 mg – 0.29 * 12 – 0.41 * 1) * (1 mmol/14 mg) = 0.06 mmol

Divide everything by the smallest number:

C = 0.29/0.06 = 4.8 ~ 5

N = 0.06/0.06 = 1

Empirical formula is:

6 0

3 years ago

The first stage of a(n) _____________________ is when clouds form; this is the cumulus stage.

alekssr [168]

Answer:

I think it might towering cumulonimbus or cumulonimbus

5 0

4 years ago

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.

maks197457 [2]

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.

Explanation:

The molecular formula of boron trifluoride is $BF_3$ .

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- $6.023x10^2^3$ atoms.

Then, 2.20 moles of boron has

- $=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms$

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

$(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol$

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

5 0

3 years ago

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

____ [38]

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

$P\cdot V = k$ (1)

Where:

$P$ - Pressure, in kilopascals.

$V$ - Volume, in cubic centimeters.

$k$ - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

$\dot P \cdot V + P\cdot \dot V = 0$ (2)

Where:

$\dot P$ - Rate of change of the pressure, in kilopascals per minute.

$\dot V$ - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

$P\cdot \dot V = -\dot P\cdot V$

$\dot V = -\left(\frac{\dot P}{P} \right) \cdot V$

If we know that $P = 180\,kPa$ , $\dot P = 30\,\frac{kPa}{min}$ and $V = 300\,cm^{3}$ , then the rate of change of the volume is:

$\dot V = -\left(\frac{\dot P}{P} \right) \cdot V$

$\dot V = -50\,\frac{cm^{3}}{min}$

The gas is decreasing at a rate of 50 cubic centimeters per minute.

3 0

3 years ago