Answer:
I do belive that it is B hrs cn I an gn
Answer:
The answer would be Igneous rock
Explanation:
Answer:
b) True. the force of air drag on him is equal to his weight.
Explanation:
Let us propose the solution of the problem in order to analyze the given statements.
The problem must be solved with Newton's second law.
When he jumps off the plane
fr - w = ma
Where the friction force has some form of type.
fr = G v + H v²
Let's replace
(G v + H v²) - mg = m dv / dt
We can see that the friction force increases as the speed increases
At the equilibrium point
fr - w = 0
fr = mg
(G v + H v2) = mg
For low speeds the quadratic depended is not important, so we can reduce the equation to
G v = mg
v = mg / G
This is the terminal speed.
Now let's analyze the claims
a) False is g between the friction force constant
b) True.
c) False. It is equal to the weight
d) False. In the terminal speed the acceleration is zero
e) False. The friction force is equal to the weight
Can you please give the phrases?
But, I'll help what I can.
First, he was the first to discover gravity. He was not bonked by the head by an apple, rather he watched an apple fall from a tree before he decided to explore gravity further.
He was also the first scientist to be knighted, which is a great honor, as you can expect.
Newton also developed The Three Laws of Motion. They are extremely important to physics and are considered some of the foundation for physics today.
He also discovered calculus, which is complex math that is very helpful to scientists today.
He also discovered the color spectrum using a glass prism, a dark room and window shade with a hole in it. He was able to project the color spectrum onto a piece of paper.
Those are the few I can think of now, but hope it helps!
Answer:
Part a)
Part b)
Ball thrown downwards =
Ball thrown upwards =
Part c)
Explanation:
Part a)
Since both the balls are projected with same speed in opposite directions
So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection
Afterwards the motion will be same as the first ball which is projected downwards
so here the time difference is given as
Part b)
Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls
so it is given as
Part c)
Relative speed of two balls is given as
now the distance between two balls in 0.8 s is given as
