Hi there!
Recall Newton's Second Law:
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
We must begin by solving for the acceleration using the following:
a = Δv/t
In this instance:
Δv = 3 m/s
t = 2.5 sec
a = 3/2.5 = 1.2 m/s²
Now, plug this value along with the mass into the equation for net force:
Answer:410 Hz
Explanation:
It is given that frequency of tuning fork is 415 Hz and hears a beat of 5 beat per second
so untuned frequency must be either 410 Hz or 420 Hz because beat frequency is the difference in frequency of two notes.
When she tightens the string the beat frequency decrease
and velocity
where
where T=tension
it T increase v also increases and from 1 st equation frequency is also increasing therefore untuned frequency must be 410 Hz because beat frequency is decreasing.
Answer:
The answer is 15N!
Explanation:
F=MA (Force = Mass * Acceleration).
F = 3 * 5 which is 15 N (newtons).
Answer:
4-mid ocean ridge at divergent plate boundaries.
Answer:
μ = 0.104
Explanation:
Given that
m = 1114 kg
s= 6.7 km = 670 m
Initial velocity ,u = 425 km/h
1 km/h= 0.27 m/s
u= 118.056 m/s
The final velocity of car ,v= 0 m/s
We know that
v² = u² + 2 a s
a=Acceleration
Now by putting the values
0² = 118.056² + 2 x a x 670
a=-\dfrac{118.056^2}{2\times 670} m/s^2
a= - 10.4 m/s²
The acceleration also given as
a = - μ g ( fr = m μ g = - m a)
10.4 = 10 x μ ( take g= 10 m/s²)
μ = 0.104
Therefore the coefficient of kinetic friction will be 0.104 .