Answer:
q=1.7346×10⁻⁶C
Explanation:
Since the electric field is perpendicular to the bottom and top of the cube,the total flux is equals the flux over the top of surface plus the flex over the lower surface
Ф(total)=Ф₃₀₀+Ф₂₃₀
But the flux is given by Ф=E.A=EACos(θ) where θ is the angle between Area vector and electric field
So
Ф(total)=E₃₀₀A Cos(180)+E₂₃₀ACos(0)
Ф(total)=A(E₃₀₀ - E₂₃₀)
The total flux is given by Gauss Law as:
Ф(total)=q/ε₀
q=ε₀Ф(total)
q=ε₀(A(E₃₀₀ - E₂₃₀))
Substitute the given values
q=(8.85×10⁻¹²){(70²)(100 - 60)}
q=1.7346×10⁻⁶C
The shadow that will be protected on the ground will represent the hawk's horizontal position. therefore it will move at the hawk's horizontal velocity component, which is:
5*cos(60) = 2.5 m/s
Penn Foster Students: Light can pass through Object B faster than it can pass through Object A
Answer:
C
Explanation:
please mark as brainliest