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3 years ago

Imagine that you drop a shot put from a tower on the moon. How much

Physics

1 answer:

ella [17]3 years ago

4 0

Answer: y = yo + Vyot + ayt = =2ay y− yo . 5. vy. 2. −voy. 2. =−2 g y− yo

Explanation: since both the displacement and acceleration are negative, they cancel each other when divided, so the result is positive. ... As you can see, as the height displacement (height) increases, the longer it takes for the robocopter to fall.

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Please help me find out this answer

Elanso [62]

The direction of work.........

4 0

3 years ago

Potassium is a crucial element for the healthy operation of the human

Dovator [93]

The second one if it’s on edge

8 0

3 years ago

Which sentence from the article supports the idea that the visible spectrum is more limited in marine animals than humans? A Mos

lidiya [134]

Most marine bioluminescence is blue-green, which is easier to see in the deep ocean

Explanation:

As per science, Emission and production of light by a living organism is defined as Bioluminescence. Bioluminescence occurs widely in marine animals whereas it is triggered by a physical disturbance is seen by humans, such as a moving boat hull or waves.

Throughout the water column bioluminescent organisms live and bioluminescence is extremely common in deep sea which shows that visible spectrum is more limited to marine animals than humans.

8 0

4 years ago

A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$

$7.05 + 30.5 = \frac{0.266}{r}$

$r = 7.08 \times 10^{-3} m$

so distance moved by the particle is given as

$d = r_1 - r_2$

$d = 0.0377 - 0.00708$

$d = 0.0306 m$

6 0

3 years ago

Explain how height,acceleration,and speed would affect the movement of a roller coaster

Lady_Fox [76]

The effective acceleration or deceleration due to gravity depends on the inclined angle of the track relative to ground; the steeper the slope is the greater the effective acceleration.

8 0

3 years ago