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icang [17]
3 years ago
10

A sample of gold has a mass of 100 grams and a volume of 5cm^3, calculate the density by dividing the mass by volume

Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0

Answer:

20cm^2

Explanation:

Here, Density= Mass/ Volume

=100/5

= 20 cm^2

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The specific heat capacity of liquid ethanol is 2.42 J/gºC.
VladimirAG [237]
Hope it helps for you : )

8 0
2 years ago
A philosophy of life which, by rejecting the democratic concept of the mass-man, endeavors to give this earth to the best nation
Julli [10]

Answer:

The correct answer is "a quote from Mein Kampf written by Adolf Hitler".

Explanation:

Mein Kampf is a 1925 famous book written by Adolf Hitler that serves as an autobiographical manifesto of the Nazi Party that he led. The statement that is included in this paragraph belongs to a quote of this book. In this statement it is reflected the ideology of Adolf Hitler, denying democracy as a government and expressing its ideology of a totalitarian autocracy.

5 0
3 years ago
If 450.0 mL of a 0.500 M solution is mixed with 200.0 mL of water, what is the molarity of the new
Oksana_A [137]

Answer:

Answer: A) .346 M

Explanation:

Given:

- 450 mL

- .5 M soln

-200 mL water

1) Convert mL to L

450 mL = .45 L

200 mL = .2 L

2) Find mols in solution

.5 M = x/.45 L

x = .225 mol

3) Find total volume of solution

.45 L + .2 L =.65 L

4) Find new molarity

molarity (M) = mols solute/ L solution

y = .225 mol (from step 2)/ .65 L (from step 3)

y = .346 M

Answer: A) .346 M

7 0
3 years ago
Here this is a clearer photo so what should I do
uysha [10]
What part of chemistry is this
8 0
3 years ago
A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure   = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol

amount of SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol

mole fraction of N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330

mole of fractionSF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669

PV = nRT

P of N_2 O = \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa

mole of SF_4=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa

Total pressure  = 39127.053 + 79126.36 = 118253.413 Pa

6 0
3 years ago
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