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maksim [4K]
3 years ago
14

The GCF of 18 and 72 is?

Mathematics
2 answers:
Serjik [45]3 years ago
4 0

Answer:

The Greast Common Factor of 18 and 72 is 18

Step-by-step explanation:

Factors of 18: 1, 2, 3, 6, 9, 18

Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

anastassius [24]3 years ago
4 0

Answer:

GCF of 18 and 72 is 18

Step-by-step explanation:

<u>To find the GCF of two or more numbers</u>

we need two steps

Step 1: List the prime factors of each number.

Step 2: Multiply those factors all numbers have in common. If there are no common prime factors, the GCF is 1.

<u>To find the GCF of 18 and 72</u>

18 = 2 * 3* 3

72 = 2 * 2 * 2 * 3 * 3

Common prime factors 2, 3, 3

Therefore GCF = 2* 3 * 3 = 18

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

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3 years ago
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kolbaska11 [484]

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Step-by-step explanation:

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2 years ago
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3 years ago
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TiliK225 [7]
Answer is A) AC= 20 and angle A=37°
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