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lesantik [10]
3 years ago
9

How are the wavelengths of light emitted?

Physics
1 answer:
Stolb23 [73]3 years ago
5 0
Wavelengths of light are emitted when an electron is coming from an energized state back to its initial state. The energy that is omitted comes in the form of the wavelength. I'm not completely sure if this is totally the way to say it, but it is what I remember from chem last year. 
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1. What are the two factors affecting friction
bija089 [108]
Answer: a.) Roughness of the surfaces in contact with each other .
Higher the roughness of surfaces in contact with each other, greater is the friction between bodies. Force of friction will be less between smooth surfaces.

b.) Weight of the sliding/rolling body: greater the weight of the moving body on the surface, more is the force of friction on the body by the surface.

I hope this helps

5 0
1 year ago
How do scientific tests help determine the properties of substance?
Maurinko [17]

There are various properties which are exhibited by substances like physical properties,chemical properties,magnetic properties,electric properties etc.

By simply observing the substance we can not get any idea about the property of a substance.One has to conduct various tests in order to reach at his or her conclusion. The scientific tests provides a better understanding about the nature of substance and the changes that happen under various conditions and parameter.

5 0
2 years ago
Read 2 more answers
12 seconds after starting from rest a frewly falling cantaloupe has a speed of
adoni [48]

Answer:

<em>The cantaloupe has a speed of 117.6 m/s</em>

Explanation:

<u>Free Fall Motion</u>

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.

Calculate the final speed:

vf=9.8 * 12 = 117.6 m/s

The cantaloupe has a speed of 117.6 m/s

3 0
2 years ago
PLEASE HELP!!!!
Sidana [21]

Answer:

B )-14000N

Explanation:

F=mv-mu

t

F =<u>2</u><u>5</u><u>5</u><u>0</u><u>(</u><u>0</u><u>)</u><u>-</u><u>2</u><u>5</u><u>5</u><u>0</u><u>(</u><u>6</u><u>)</u>

1.1

F = -13909.09

approximately -14000N

4 0
3 years ago
A jogger is running outdoors on a cold day when the temperature is -20.0°C. She is breathing at the rate of 25 breaths per minut
Katyanochek1 [597]

Answer: 168606 J

Explanation:

Amount of heat lost is given by:

Q = m c ΔT

where, m is the mass of air inhaled, c is the specific heat of air and ΔT is the change in the temperature.

First, we will calculate the mass of air inhaled.

In each breath, jogger inhales 0.00450 m³ of air.

Breathing rate = 25 breathes per minute.

She jogs for 20 minutes.

So amount of air inhaled = 25 breathes per minute × 20 minutes × 0.00450 m³

Mass of air inhaled = density of air × volume of air inhaled

⇒ m = 1.29 kg/m³× 25 breathes per minute × 20 minutes × 0.00450 m³  

⇒ m = 2.9 kg

Now, ΔT = T₂-T₁

T₁ = -20⁰C = -20 +273 K = 253 K

T₂ = 37⁰C = 37+273 K = 310 K

⇒ ΔT = T₂-T₁ = 310 K- 253 K = 57 K

Q = m c ΔT

⇒ Q = 2.9 kg × 1020 J/kg.K × 57 K = 168606 J

Thus, the jogger losses 168606 J amount of heat from breathing during 20 minutes of jogging.

3 0
3 years ago
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