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3 years ago

WILL GIVE BRAINLY!! PLEASE HELPP

1 answer:

8 0

The purpose of the machine is to leverage its mechanical advantage such that the force it outputs to move the heavy object is greater than the force required for you to input.

But there's no such thing as a free lunch! When you apply the conservation of energy, the work the machine does on the object will always be equal to (in an ideal machine) or less than the work you input to the machine.

This means that you will apply a lesser force for a longer distance so that the machine can supply a greater force on the object to push it a smaller distance. That is the trade-off of using the machine: it enables you to use a smaller force but at the cost of having to apply that smaller force for a greater distance.

The answer is: The work input required will equal the work output.

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PLEASE HELP - basic SUVAT stuff

Goryan [66]

Answer:

1. 5 m/s

2. 8 m/s

3. 10 s

4. 3 m/s

Explanation:

1. Average speed = distance / time

s = 20 m / 4 s

s = 5 m/s

2. First, find the time to travel from A to B:

60 m = 10 m/s × t

t = 6 s

Now find the average speed from A to C:

s = 80 m / (6 s + 4 s)

s = 8 m/s

3. If t is the time traveling from C back to B, and the average speed of the whole trip is 5 m/s, then:

5 m/s = 100 m / (6 s + 4 s + t)

t = 10 s

4. Average velocity = displacement / time

v = 60 m / 20 s

v = 3 m/s

6 0

3 years ago

Middle C also known as "do" on the fixed do-solfege scale, is a note used when playing or singing music. The frequency of middle

saveliy_v [14]

Answer:

198.2m/s

Explanation:

Speed of a wave(v) is the product of the frequency of the wave (f) and its wavelength(¶).

Mathematically, v = f/¶

Given frequency of the middle C = 261.63Hz

Wavelength = 131.87cm

Converting this to meters we have;

131.87/100 = 1.32m

Speed of the sound = 261.63/1.32

Speed of the sound = 198.20m/s

Therefore the speed of sound for middle C is 198.2m/s

8 0

4 years ago

A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh

andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by $\frac{1}{2}QC$ where $Q$ is the charge on it and $C$ is its capacitance. The capacitance is defined, geometrically, as

$\dfrac{\epsilon A}{d}$

where $\epsilon$ is a constant that is determined by the material between the plates, $A$ is the area of the plates and $d$ is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, $C_1$ at initial separation, $d_1$