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Lena [83]
3 years ago
9

A woman stands on a scale in a moving elevator. Her mass is 61.0 kg, and the combined mass of the elevator and scale is an addit

ional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9850 N. What does the scale read during the acceleration?
Physics
1 answer:
vazorg [7]3 years ago
7 0
First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24

the read of the scale during the acceleration is :


mg + ma

= (61 kg x 9.8) +  (61 kg x 11.24)
= 1283.4 N

hope this helps
 
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Answer:

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Explanation:

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The work is equal to the product of the force times the distance and the cosine of the angle that exists between the direction of the force and the direction that the moving point or object travels:

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Work W is measured in joules (J), force is measured in newtons (N), and displacement in meters (m).

In this case:

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Replacing:

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Solving:

W= 689.44 J

<u><em>She does a work of 689.44 J in the snow.</em></u>

7 0
3 years ago
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Answer:

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\beta=8.86\times10^{9}

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Using formula of tunnel barrier

T=\dfrac{16E(V_{0}-E)}{V_{0}^2}e^{-2\beta a}

Put the value into the formula

T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times0.5\times10^{-9}}

T=5.45\times10^{-4}

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T=\dfrac{16\times 2(5.0-2.0)}{5.0^2}e^{-2\times8.86\times10^{9}\times1.00\times10^{-9}}

T=7.74\times10^{-8}

Hence, The tunnel probability for 0.5 nm and 1.00 nm are  5.45\times10^{-4} and 7.74\times10^{-8} respectively.

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