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Lena [83]
3 years ago
9

A woman stands on a scale in a moving elevator. Her mass is 61.0 kg, and the combined mass of the elevator and scale is an addit

ional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9850 N. What does the scale read during the acceleration?
Physics
1 answer:
vazorg [7]3 years ago
7 0
First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24

the read of the scale during the acceleration is :


mg + ma

= (61 kg x 9.8) +  (61 kg x 11.24)
= 1283.4 N

hope this helps
 
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velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

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Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

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and $ V_y=\frac{160}{3}$  m/s

Therefore, velocity is = $ \sqrt{V_x^2 + V_y^2} $

                                   = $ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $

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And direction is

tan θ = $ \frac{V_y}{V_x}$     = 1.6

therefore, $ \theta = \tan^{-1}1.6 $

                   = $ 58 ^{\circ}$  from x-axis

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