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3 years ago

Asexual reproduction provides an advantage to organisms under which of the following conditions?

Physics

1 answer:

krek1111 [17]3 years ago

4 0

Answer:

The organisms are widely dispersed in the habitat and rarely encounter each other...

Explanation:

As asexual reproduction needs only 1 parent.. they can do it on their own.. without encountering their mates

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What is a single cell organism able to do?

Sunny_sXe [5.5K]

Survived on its own.

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3 years ago

Read 2 more answers

Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 39.9° wit

wariber [46]

Answer:

n=2.053

Explanation:

We will use Snell's Law defined as:

$n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}$

Where n values are indexes of refraction and $\theta$ values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:

$1*Sin(39.9)=n_{2}*Sin(18.2)$

Solving for $n_{2}$ yields:

$n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053$

Remember to use degrees for trigonometric functions instead of radians!

6 0

3 years ago

How does changing the lengthy but not the height of an inclined plane affect the work done to lift a load? PLZ HELP ME NOW'

Serhud [2]

Answer: Work Done would remain same.

Let us assume that the velocity is constant while taking the load up the inclined plane. Then, the kinetic energy would remain the same. This is because kinetic energy is dependent on velocity $(K.E.=\frac{1}{2}mv^2)$ . If that is constant, the kinetic energy would remain same. The potential energy is dependent on the height $(P.E.=mgh)$ . If the height is changed, then potential energy varies. In the question, it is mentioned that without changing the height, the length of the inclined plane is changed. Therefore, the potential energy would be same as before.

We know, work done is equal to potential energy plus kinetic energy. Since there is no change in any of these, the required work done would not change.

4 0

3 years ago

Which statement about the minerals plagioclase feldspar, gypsum, biotite mica, and talc can best be inferred from the chart? (1)

madreJ [45]

Answer:

(4) The physical and chemical properties of these minerals determine how humans use them.

Explanation:

All the materials and the metals found on earth shows certain characteristics naturally or in their physical state. These physical characteristics can be their look, their structure, their color, strength, melting point, boiling point, density, etc.

And chemical properties of the metals are defined as those characteristics or features of the metals that it exhibits when these metals reacts chemically.

The physical properties as well as the chemical properties distinguishes each metal from each other. These properties determines how people use these metals in their life.

7 0

3 years ago

Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that t

ArbitrLikvidat [17]

Answer:

The temperature of the steam during the heat rejection process is 42.5°C

Explanation:

Given the data in the question;

the maximum temperature T $_H$ in the cycle is twice the minimum absolute temperature T $_L$ in the cycle

T $_H$ = 0.5T $_L$

now, we find the efficiency of the Carnot cycle engine

η $_{th$ = 1 - T $_L$ /T $_H$

η $_{th$ = 1 - T $_L$ /0.5T $_L$

η $_{th$ = 0.5

the efficiency of the Carnot heat engine can be expressed as;

η $_{th$ = 1 - W $_{net$ /Q $_H$

where W $_{net$ is net work done, Q $_H$ is is the heat supplied

we substitute

0.5 = 60 / Q $_H$

Q $_H$ = 60 / 0.5

Q $_H$ = 120 kJ

Now, we apply the first law of thermodynamics to the system

W $_{net$ = Q $_H$ - Q $_L$

60 = 120 - Q $_L$

Q $_L$ = 60 kJ

now, the amount of heat rejection per kg of steam is;

q $_L$ = Q $_L$ /m

we substitute

q $_L$ = 60/0.025

q $_L$ = 2400 kJ/kg

which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)

q $_L$ = h $_{fg$ = 2400 kJ/kg

now, at h $_{fg$ = 2400 kJ/kg from saturated water tables;

T $_L$ = 40 + ( 45 - 40 ) ( $\frac{2400-2406.0}{2394.0-2406.0}\\}$ )

T $_L$ = 40 + (5) × (0.5)

T $_L$ = 40 + 2.5

T $_L$ = 42.5°C

Therefore, The temperature of the steam during the heat rejection process is 42.5°C

4 0

3 years ago