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2 years ago

Asexual reproduction provides an advantage to organisms under which of the following conditions?

Physics

1 answer:

krek1111 [17]2 years ago

4 0

Answer:

The organisms are widely dispersed in the habitat and rarely encounter each other...

Explanation:

As asexual reproduction needs only 1 parent.. they can do it on their own.. without encountering their mates

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How was mount Everest made? Please i am handing out 100 points

Simora [160]

Answer:

Mount Everest formed from a tectonic smashup between the Indian and Eurasian tectonic plates tens of millions of years ago.

Explanation:

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2 years ago

Can a falling object reach terminal velocity in outer space? Explain.

Damm [24]

Ith air resistance acting on an object that has been dropped, the object will eventually reach a terminal velocity, which is around 53 m/s (195 km/h or 122 mph) for a human skydiver. ... (On the Moon, the gravitational acceleration is much less than on Earth, approximately 1.6 m/s2.)

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2 years ago

The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o

kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

$Y=Ae^{-kt}$

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

$\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}$

$Y=Ae^{-kt}$

$\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years$

hence time taken is equal to 14,156 years

5 0

3 years ago

A violinist is tuning her instrument to concert A (440 Hz). She plays the note while listening to an electronically generated to

Soloha48 [4]

To solve the problem it is necessary to take into account the concepts related to beat frequency, i.e., The number of those wobbles per second.

The equation that describes the beat frequency is

$f_{beat} = |f_2-f_1|$

For our given case we have that the frequency of the instrument is 440Hz and the Beat frequency is 5Hz therefore,

A) The frequency of the violin would be given by

$f_{beat} = |f_2-f_1|$

$5Hz = |f_2-440Hz|$

$f_2 = 440 \pm 5$

$f_2 = 445Hz or 435Hz$

B) <em>The violinist must loosen the string.</em> As the tightening increases the frequency, thereby increasing the number of beats from 5 to 6, i. e, on thightening the string, the frequency further increases as high frequency will be produced by short trings.

5 0

3 years ago

If 478 watts of power are used in 14 seconds, how much work was done?

sergiy2304 [10]

" 478 watts " means 478 joules per second.

In 14 seconds, the total work or energy is (14 x 478) = <em>6,692 joules</em>

7 0

3 years ago