Problem: A lossless 50-Ω transmission line is terminated in a load with ZL = (50 + j25) Ω. Use the Smith chart to find the follo
wing: (a) The reflection coefficient Γ. (b) The standing-wave ratio. (c) The input impedance at 0.35λ from the load. (d) The input admittance at 0.35λ from the load. (e) The shortest line length for which the input impedance is purely resistive. (f) The position of the first voltage maximum from the load.
1 answer:
Answer: (a). ΓL = 0.246 < 75°
(b). S = 1.7
(c). Zin = (30-j)λ
(d). jreal = Arc Po = 0.105λ
(e). jmax = jreal = 0.105λ
Explanation:
attached is a document to help in understanding.
So we will begin with a step by step analysis of the problem.
from the diagram we have that ZL = (50 + j25) Ω.
where ZL = ZL / Z₀ = 50 + j25 / 50 = 1 + j0.5
so we mark this on the chart as point 'P'
(a) ΓL = mP/m 'P' < Θ L = 1.7/6.9 < 75°
ΓL = 0.246 < 75°
(b) This s-circle 's' is given thus s = r = 1.7 on the RHS of the chart
S = 1.7
(c) we are to calculate the input impedance;
ζin = Q = 0.6 - j0.02
therefore Zin = Z₀ζin = 50(0.6 - j0.02) = (30-j)λ
Zin = (30-j)λ
(d) here we are taking R as the diameter opposite of Q on the s=circle
so R = γin = 1.7 + j0.02
yin = yo (γin) = (1.7+j0.02) / 50 = (34 + j0.4)ms
yin = (34 + j0.4)ms
(e) move from 'p' on s-circle to 'o'
where maximum impedance = Znxl = Zos
which gives jreal = Arc Po = 0.105λ
(f) jmax = jreal = 0.105λ
cheers i hope this helps
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