V(final)=V₀+a(t), V(final)=28, V₀=0, t=3.3, solve for a. a=28/3.3=8.5m/s^2. F=ma, F=?, m=590kg, a=8.5m/s^2, F=5015N.
Rate of change = (amount of change) / (time for the change)
Amount of change = (temp at the end) minus (temp at the beginning)
Amount of change = (70°F) minus (62°F) = 8°F
Time for the change = (time at the end) minus (time at the beginning)
Time for the change = (1200 - 0800) = 4 hours
Rate of change = (8°F) / (4 hours)
Rate of change = 2°F per hour
Answer:
The correct answer is option ( D ) Yoga
Explanation:
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Answer:
(a)0.0675 J
(b)0.0675 J
(c)0.0675 J
(d)0.0675 J
(e)-0.0675 J
(f)0.459 m
Explanation:
15g = 0.015 kg
(a) Kinetic energy as it leaves the hand

(b) By the law of energy conservation, the work done by gravitational energy as it rises to its peak is the same as the kinetic energy as the ball leave the hand, which is 0.0675 J
(c) The change in potential energy would also be the same as 0.0675J in accordance with conservation law of energy.
(d) The gravitational energy at peak point would also be the same as 0.0675J
(e) In this case as the reference point is reversed, we would have to negate the original potential energy. So the potential energy as the ball leaves hand is -0.0675J
(f) Since at the maximum height the ball has potential energy of 0.0675J. This means:
mgh = 0.0675
0.015*9.81h = 0.0675
h = 0.459 m
The ball would reach a maximum height of 0.459 m
It is beacuse of fluid If there is no fluid, there is no drag. Drag is generated by the difference in velocity between the solid object and the fluid. If this statement is correct then how can there be drag in space if there is no air?