Answer: chemistry
Explanation: see definition on wikipedia.
Answer: In an experiment, mice were fed glucose (C6H12O6) containing a small amount of radioactive carbon. The mice were closely monitored, and in a few minutes, radioactive carbon atoms showed up in _Carbon dioxide/Carbon IV oxide (CO2)_
Explanation: The end product of Glucose at the end of metabolism is Carbon dioxide, water and ATP.
C6H12O6 + 6O2 ----------> 6CO2 + 6H2O + ATP (Energy)
The carbon is converted to Carbon dioxide. So, the radioactive Carbon appears in the Carbon dioxide/Carbon IV oxide (CO2).
Answer:
I believe the answer would be D
Explanation:
The reason why is that I divided 5.75 with 5 which results in 1.15
Answer:
B
Explanation:
Isotopes have the same number of protons but different number of neutrons.
Answer:
C
Explanation:
add them together and multiply by 2