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zavuch27 [327]
3 years ago
6

Find the lateral area and surface area of a regular triangular prism with base edge 7 cm, a base height 6.1 cm and prism height

of 11 cm. Round to the nearest tenth.
Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0

Lateral Area: 288 cm

Total Surface Area: 331 cm

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What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?
Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Let (x_1,y_1) be the point (3.5, 2.2) and (x_2, y_2) be the point (1.5, -4.8)

substituting the points in the formula

M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)

=\left(\frac{5}{2}, \frac{-2.6}{2}\right)

=\left(2.5,-1.3\right)

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

8 0
3 years ago
write the slope - intercept equation of the line that passes through the point (6, "-1)" and has a slope of "-1/3"
TEA [102]

Answer:

y = - \frac{1}{3} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{1}{3} , then

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, - 1 ) into the partial equation

- 1 = - 2 + c ⇒ c = - 1 + 2 = 1

y = - \frac{1}{3} x + 1 ← equation of line

8 0
2 years ago
Consider a simple example of moral hazard. Suppose that Woodrow goes into a casino to make one bet a day. The casino is very bas
Neko [114]

Answer:

The expected value of the safe bet equal $0

Step-by-step explanation:

If  

S=\left\{s_1,s_2,...,s_n\right\}

is a finite numeric sample space and

P(X=s_k)=p_k for k=1, 2,..., n

is its probability distribution, then the expected value of the distribution is defined as

E(X)=s_1P(X=s_1)+s_2P(X=s_2)+...+s_nP(X=s_n)X)

What is the expected value of the safe bet?

In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is

S = {100,-100}

Since the coin is supposed to be fair,  

P(X=100)=0.5

P(X=-100)=0.5

and the expected value is

E(X) = 100*0.5 - 100*0.5 = 0

6 0
3 years ago
How is 7.54÷4= 1.88<br><br>I got 1.88 with the remainder of 2​
Naddika [18.5K]

Answer:

I got 1.885 for the answer.

Maybe they wanted it rounded to just 2 decimal places.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Remember to check for extraneous solutions
larisa86 [58]

Domain:v\neq0\\\\\dfrac{2}{v}+\dfrac{2}{3}=\dfrac{v-6}{3v}\\\\\dfrac{2\cdot3}{v\cdot3}+\dfrac{2\cdot v}{3\cdot v}=\dfrac{v-6}{3v}\\\\\dfrac{6}{3v}+\dfrac{2v}{3v}=\dfrac{v-6}{3v}\\\\\dfrac{6+2v}{3v}=\dfrac{v-6}{3v}\iff6+2v=v-6\qquad\text{subtract 6 from both sides}\\\\2v=v-12\qquad\text{subtract v from both sides}\\\\\boxed{v=-12}\to\boxed{A.}

3 0
3 years ago
Read 2 more answers
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