suppose a spherical snowball with a diameter of 6 centimeters is melted in a large bowl. the resulting water is then poured into
2 answers:
Oooh fun!
Alright,
formula for a sphere is (4
r^3)3
4*pi*6^3=2714.34/3
904.78
Now you can do this 2 ways. First is that a cone is 1/3 of a sphere with the same radius so just take 904.78 and multiply it by 1/3 and then by 2 to get 2/3 of it or do this.
cone~ (6^2*pi*10)/3
376.99
and subtract
<span>904.78-376.99=527.79
</span>
<span>527.79^3 greater. Check my math. I could be wrong.</span>
Alright,
formula for a sphere is (4
4*pi*6^3=2714.34/3
904.78
Now you can do this 2 ways. First is that a cone is 1/3 of a sphere with the same radius so just take 904.78 and multiply it by 1/3 and then by 2 to get 2/3 of it or do this.
cone~ (6^2*pi*10)/3
376.99
and subtract
<span>904.78-376.99=527.79
</span>
<span>527.79^3 greater. Check my math. I could be wrong.</span>
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Answer:
B.
Step-by-step explanation:
Total number of students surveyed = 420
Of which only prefer rap.
So, the number of people who like rap is the product of the fraction of people who prefer rap and the total number of students.
The number of students that prefer rap is 105
So the equation is .
The missing part of the question is show in bold format.
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it
once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.
You roll it 500 times and get the following data:
Outcome 1 2 3 4 5 6
Frequency 77 92 75 90 76 90
Exercises 1–2
1. If the equality model was correct, about how many of each outcome
would you expect to see if the cube is rolled 500 times
2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?
Answer:
Step-by-step explanation:
1.
If the equally likely model was correct, about how many of each outcome
would you expect to see if the cube is rolled 500 times.
The probability of rolling any of the numbers from 1 to 6 is p(1/6)
The number of each of the outcomes expected to be seen in 500 rolls of the number cube is
2. From the given data in the roll;
The odd numbers 1, 3 and 5, were obtained at 77, 75 and 76 times respectively.
Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228
Probability of an odd number turning up =
=
= 0.456
= 45.6%
The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.
The total number of times even number were rolled = 92 + 90 + 90 = 272
Probability of an even number turning up =
=
= 0.544
= 54.4%