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Luba_88 [7]
3 years ago
12

Determine the freezing point of a 0.765 m solution of nitrobenzene in naphthalene. (given: naphthalene Kf = 7.45o C Kg/ mole and

the pure freezing point is 80.3o C) Report answers to one decimal place.
Chemistry
1 answer:
amid [387]3 years ago
7 0

Answer: The freezing point of a 0.765 m solution of nitrobenzene in naphthalene is 74.6^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(80.3-T_f)^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte such as nitrobenzene)

K_f = freezing point constant = 7.45^0C/m

m= molality  = 0.765

(80.3-T_f)^0C=1\times 7.45\times 0.765

T_f=74.6^0C

Thus the freezing point of a 0.765 m solution of nitrobenzene in naphthalene is 74.6^0C

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Propose a structure for an aromatic hydrocarbon, C9H12, that can form two C9H11Cl products on substitution of a hydrogen on the
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Answer:

Explanation:

From the given study,

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the first process we suppose to carry out is to calculate the double bond equivalence.

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Learn more: brainly.com/question/4933048

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