The rules of IUPAC followed for hydrocarbon are
a) We will first find out the longest chain of carbon in the given organic compound including triple bond
the root name will be "hex" as number of carbon atoms in longest chain is six.
b) The triple bond will be assigned minimum number locant. the locant will be 2 .
The primary suffix will be "yne"
hence
hex-2-yne
c) we will give locant number to methyl group (present as substituent)
it will be "4"
Thus the completer IUPAC name will be
4-methylhex-2-yne or 4-methyl-2-hexyne [as given in the options]
Answer:
See explanation and image attached
Explanation:
The reaction of 1-bromo-2-tert-butylcyclohexane with potassium tert-butoxide is an elimination reaction that occurs by E2 mechanism.
The E2 reaction proceeds faster when the hydrogens are in an antiperiplanar position at an angle of 180 degrees.
This is only attainable in the trans isomer of 1-bromo-2-tert-butylcyclohexane. Hence trans 1-bromo-2-tert-butylcyclohexane reacts faster with potassium tert-butoxide
Answer:
Hybridization: sp
Electron geometry: linear
Molecular geometry: linear
Explanation:
H₃CCCH can also be written as its Lewis structure which is shown in the figure attached. The figure shows that the central carbon atom makes a single bond with CH₃ and a triple bond with CH. This means that the hybridization of the carbon is sp and both the electron and molecular geometry are linear with an 180° bond angle.
