The entire race is 1 full race.
One full race is 1.
He ran 3/8 of 1, so he ran 3/8.
He needs to run the rest of the race.
The rest is unknown, so we call it x.
When you add 3/8 to the unknown, you get the full race.
The equation is
x + 3/8 = 1
Change 1 to a denominator of 8.
x + 3/8 = 8/8
Subtract 3/8 from both sides.
x = 5/8
Answer: He still needs to run 5/8 of the race.
Answer:
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Step-by-step explanation:
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The angle between two vectors is:
CosФ = u - v / Magnitude(u) x magnitude(v)
Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)
Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)
u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11
cosФ = -11 / sqrt(53) x sqrt(5)
cosФ = -11sqrt265) / 265
Ф =cos^-1(-11sqrt265) / 265)
Ф=132.51 degrees.
Answer:
x = -8 and BDC is 68 degrees.
Step-by-step explanation:
Combine -7x+12 and -8x+48 to get -15x+60. Since BDA is a straight angle put the above equation to get -15x+60=180. Subtract 60 from both sides to get -15x=120. Divide -15 both sides to get -8 as your x value. Plug in -8 to BDC, since both negatives are being multiplied, it would turn to a positive number which is 56, add 12 to get 68 as your final result for BDC.
Answer:
James bought 11 good tickets and 5 bad tickets.
Step-by-step explanation:
Given that:
Cost of each good ticket = $8
Cost of each bad ticket = $5
Total amount spent = $113
Total tickets bought = 16
Let,
x be the number of good tickets bought
y be the number of bad tickets bought
x+y=16 Eqn 1
8x+5y=113 Eqn 2
Multiplying Eqn 1 by 5
5(x+y=16)
5x+5y=80 Eqn 3
Subtracting Eqn 3 from Eqn 2
(8x+5y)-(5x+5y)=113-80
8x+5y-5x-5y=33
3x=33
Dividing both sides by 3
Putting x=11 in Eqn 1
11+y=16
y=16-11
y=5
Hence,
James bought 11 good tickets and 5 bad tickets.
