Answer:
Find attached the solution
Explanation:
A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force
of static friction f on the block?
A) f > mg
B) f = mgsin(?)
C) f > mgcos(?)
D) f = mgcos(?)
E) f > mgsin(?)
A) f > mg
B) f = mgsin(?)
C) f > mgcos(?)
D) f = mgcos(?)
E) f > mgsin(?)
1 answer:
Answer:
Option B
Explanation:
For a system of block on inclined ramp shown in the attached image. From the attached image, the Normal force N, weight mg and frictional force f act on the block. The sum of vertical forces should be zero just as sum of vertical forces should be zero when the system is in equilibrium condition.
Taking sum of forces along the inclined plane we deduce that
[tex]f=mgsin \theta [tex]
Therefore, option B is the correct option.
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Answer:
Condition
Explanation:
Basically black hole is an object from which light rays can not escape it means to go out from gravitational field , that body should thrown with speed greater then light.
Let's do some calculation
Gravitational potential at surface =
If we give kinetic energy equal to magnitude of Potential energy as on surface it will escape.
=
⇒
It will be more better for black hole if above ratio (analogous to density ) is more then above calculated
(a) 2 Hz
The frequency of the nth-harmonic is given by
where
is the fundamental frequency
Therefore, the frequency of the third harmonic of the A () is
while the frequency of the second harmonic of the E () is
So the frequency difference is
(b) 2 Hz
The beat frequency between two harmonics of different frequencies f, f' is given by
In this case, when the strings are properly tuned, we have
- Frequency of the 3rd harmonic of A-note: 1320 Hz
- Frequency of the 2nd harmonic of E-note: 1318 Hz
So, the beat frequency should be (if the strings are properly tuned)
(c) 1324 Hz
The fundamental frequency on a string is proportional to the square root of the tension in the string:
this means that by tightening the string (increasing the tension), will increase the fundamental frequency also*, and therefore will increase also the frequency of the 2nd harmonic.
In this situation, the beat frequency is 4 Hz (four beats per second):
And since the beat frequency is equal to the absolute value of the difference between the 3rd harmonic of the A-note and the 2nd harmonic of the E-note,
and , we have two possible solutions for
:
However, we said that increasing the tension will increase also the frequency of the harmonics (*), therefore the correct frequency in this case will be
1324 Hz