initial acceleration of rocket is given as
a = 12 m/s^2
h = 26 m
now we can use kinematics to find its speed
now after this it will be under free fall
so now again using kinematics
at maximum height
total height from the ground = 31.8 + 26 = 57.8 m
Part b)
now after reaching highest height it will fall to ground
So in order to find the speed we can use kinematics again
Part c)
first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s
now we have
after this it will reach to highest point and final speed becomes zero
now from this it will fall back to ground and reach to final speed 33.67 m/s
now we have
so total time is given as
<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>
Answer:
B I believe, because the axe is wedged into the log
Answer:
The flea will reach to a height of 5.2 cm.
Explanation:
Let us assume it is given that, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.
Initial speed, u = 1 m/s
Initial distance, x = 0.5 mm
We need to find the height reached by the flea. Using third equation of motion to find it.
At maximum height, its final speed, v = 0
Here, a = -g
or
h = 5.2 cm
So, the flea will reach to a height of 5.2 cm.
Wavelength = 600 nm = 600 × 10^(-9)
speed of light = c = 3 × 10^8
planck constant = h = 6.63 × 10^(-34)
energy of photon = hc/wavelength
= 6.63 × 10^(-34) × 3 × 10^8/600 × 10^(-9)
= 1.9 × 10^(-25)/6 × 10^(-7)
= 0.31 × 10^(-16)
= 3.1 × 10^(-17)
