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agasfer [191]
4 years ago
6

3.

Physics
1 answer:
Greeley [361]4 years ago
8 0

Answer:

90 m/s

8100 m

Explanation:

Given:

v₀ = 0 m/s

a = 0.5 m/s²

t = 3 min = 180 s

Find: v and Δx

v = at + v₀

v = (0.5 m/s²) (180 s) + 0 m/s

v = 90 m/s

Δx = v₀ t + ½ at²

Δx = (0 m/s) (180 s) + ½ (0.5 m/s²) (180 s)²

Δx = 8100 m

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<u>Explanation:</u>

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Now,

             T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}

As, planet mass is equal to 0.7 times the sun mass, so

            T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}

Taking the ratios of both equation, we get,

             \frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}

            \frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}

            \left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}

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Given T_{p}=9.5 \text { days } and T_{e}=365 \text { days }

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         r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}

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