If the tow truck is pulling the car, the acceleration rate of the car is the same as the tow truck
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Answer:
D) Electromagnetic waves
Explanation:
This is because with compression waves and longitudinal waves a medium is required such as air. however in a vacuum this will not work
Answer:
Explanation:
Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:
This means the absolute zero point of the Kelvin scale is
Keeping this in mind, we have the freezing point and boling point of Methane as:
Freezing point:
Boiling point:
According to this, there is a linear relation between the methane scale () and the Kelvin scale in the form:
(1)
Where:
is the temperature in Kelvin
is the temperature in degrees Methane
Firstly, we need to find the value of and with the two given points ( and ):
When and :
(2)
When and :
(3)
Now we have the linear equation:
(4)
Isolating :
(5)
Evaluating for :
(6)
Finally:
This means
Answer:
It is (1/5)th as much.
Explanation:
If we apply the equation
F = G*m*M / r²
where
m = mass of a man
M₀ = mass of the planet Driff
M = mass of the Earth
r₀ = radius of the planet Driff
r = radius of the Earth
G = The gravitational constant
F = The gravitational force on the Earth
F₀ = The gravitational force on the planet Driff
g = the gravitational acceleration on the surface of the earth
g₀ = the gravitational acceleration on the surface of the planet Driff
we have
F₀ = G*m*M₀ / r₀² = G*m*(5*M) / (5*r)²
⇒ F₀ = G*m*M / (5*r²) = (1/5)*F
If
F₀ = (1/5)*F
then
W₀ = (1/5)*W ⇒ m*g₀ = (1/5)*m*g ⇒ g₀ = (1/5)*g
It is (1/5)th as much.
Answer:
the work done by the net external force acting on the skier is 3046.12 J.
Explanation:
Given;
initial speed of the water skier, u = 6.3 m/s
final speed of the water skier, v = 10.9 m/s
mass of the water skier, m = 77 kg
The work done by the net external force is calculated as;
W = ΔK.E
Therefore, the work done by the net external force acting on the skier is 3046.12 J.