To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.
The tension in the vertical plane will be equivalent to the centripetal force therefore

Here,
m = mass
v = Velocity
r = Radius
The tension in the horizontal plane will be subject to the action of the weight, therefore

Matching both expressions with respect to the tension we will have to


Then we have that,


Rearranging to find the velocity we have that

The value of the angle is 14.5°, the acceleration (g) is 9.8m/s^2 and the radius is



Replacing we have that


Therefore the speed of each seat is 4.492m/s
The answer is D.
I hope this helps.
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.
Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)
The unit for velocity (to be used here) is m/s or ms⁻¹
I believe the answer is A.
Hope This Helps! Have A Nice Day!!