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3 years ago

Combine like terms: 4f + 3e - 2f - e

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

2f + 2e

that’s the answer

Hitman42 [59]3 years ago

7 0

Answer:

2f + 2e

Step-by-step explanation:

4f -2f = 2f

3e - 1e = 2e

2f + 2e

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Reuben has bought 30 pounds of dog food. He feeds his dog 3/5 pounds for each meal. For how many meals will the food last?

egoroff_w [7]

Answer:

Step-by-step explanation:

3*50=150. 150/5=30 pounds

8 0

2 years ago

Answer for a cookie ;)

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

but i will still take the cookie

4 0

3 years ago

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

4 years ago

Mr.martland decides the length of his square vegetable garden will be 17 ft. He calculates that the area of the garden is 34 ft^

stira [4]

Answer:

Nope

Step-by-step explanation:

If it is a square garden, all sides are equal. Area would be 17x17 and that would equal $289^{2} ft$ not 34

3 0

3 years ago

Compute x/y if

Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

${:\implies \quad \sf x+\dfrac{1}{y}=4}$

Multiplying both sides by y will lead ;

${:\implies \quad \sf xy+1=4y}$

${:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}$

Now, consider the second equation which is ;

${:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}$

Multiplying both sides by x will yield

${:\implies \quad \sf xy+1=\dfrac{x}{4}}$

${:\implies \quad \sf xy=\dfrac{x}{4}-1}$

${:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}$

As LHS of both equations (i) and (ii) are same, so equating both will yield;

${:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}$

Multiplying both sides by 4 will yield

${:\implies \quad \sf 16y-4=x-4}$

${:\implies \quad \sf 16y=x}$

Dividing both sides by y will yield :

${:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}$

Hence, the required answer is 16

5 0

2 years ago

Combine like terms: 4f + 3e - 2f - e​

Combine like terms: 4f + 3e - 2f - e