Answer:
c
Explanation:
use %composition given to calculate emperical 4mular
<h2>Answer with explanation </h2>
<h3><em>The starting diol for this molecule is :-</em></h3><h3><em>The starting diol for this molecule is :-D) ethan-1,2-diol.</em></h3>
<em>Hope </em><em>my </em><em>answer </em><em>is</em><em> helpful</em><em> to</em><em> you</em><em> </em><em>☺️</em>
You have to be very careful with this question. A change in mass can also occur in chemical changes especially if you have too much of something. For example
CH4 + 1.5 02 ===> CO2 + H2O
If you have too much of either CH4 or O2, there will be some CH4 or O2 left over. There has been a change in mass that you have too much of.
However that is not the point of the question. It is just something you need to be aware of.
Suppose you have a piece of aluminum and you take a course grinder after it. You will change the texture of the side you took the grinder to. If the aluminum has been anodized (a color has been put on it's surface), you may grind the color off or if it is just plain aluminum, you may roughen the surface, but you won't change what the aluminum will do chemically.
You may need only a small portion of the aluminum and you grind off just what you need. That will change the mass of both what you took off and the piece that you want, but the aluminum will still do whatever chemical property you need to use.
So you can change both texture and mass without changing the chemical properties of the substance whose mass or texture you are changing.
Answer:
6.0 L
Explanation:
For this question, we can use
P1×V1= P2 × V2
where
P1 (initial pressure)= 0.2 kPa
V1 (initial volume)= 15L
P2 (final pressure)= 0.5 kPa
V2(final volume)= ?
Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.
V2= (P1 × V1)/ P2
V2= (0.2 ×15)/0.5
V2 =6 L
