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2 years ago

Which statement describes the bonds in iron sulfate, FeSO4?

Chemistry

1 answer:

Feliz [49]2 years ago

5 0

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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
Covalent bonds: they are formed between nonmetals, which share electrons.

Regarding the bonds in FesO₄:

Fe is a metal and S a nonmetal, thus they will form ionic bonds.
S and O are both nonmetals, thus they will form covalent bonds.

Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Learn more: brainly.com/question/23882847

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Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50

devlian [24]

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C $_{V}$ You can work out C $_{V}$

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC $_{V}$ ∆T

Polyatomic gas: C $_{V}$ = 3R

∆U= nC $_{V}$ ∆T

∆U= 28g x C $_{V}$ x (350K - 58.3K)

∆U = 28C $_{V}$ x 291.7

∆U = 10967.6 x C $_{V}$

5 0

3 years ago

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Katyanochek1 [597]

Answer:

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2 years ago

What did rutherford learn about the atom from his gold-foil experiment?

cluponka [151]

Hi there!

Rutherford's experiment showed that the atom's nucleus did have a positive charge. The α particles' trajectory was altered when it went through the gold foil, which, in turn resulted in the discovery of the atom's positive charge.

I hope this helps!
Brady

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3 years ago

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musickatia [10]

Answer:

here's a great idea!

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2 years ago

In a stadium, fans stand up and sit down to produce a wave across the stadium. This type of wave where the material travels perp

elena-14-01-66 [18.8K]

Transverse wave is a wave vibrating at right angles to the direction of its propagation.

In short, Your Answer would be Option B

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3 years ago

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