Question

Questions in photo pls help me its due tomorrow.

Answer 1

Step-by-step explanation:

Hey there!

Given;

${2}^{4x - 1} =32$

${2}^{4x} . {2}^{ - 1} = {2}^{5}$

${2}^{4x} . \frac{1}{2} = {2}^{5}$

${2}^{4x} = {2}^{5} . {2}^{1}$

${2}^{4x} = {2}^{6}$

$4x = 6$

$x = \frac{6}{4}$

$x = \frac{3}{2}$

7.)

$\sqrt{x} - 3 = 7$

$\sqrt{x} = 7 + 3$

$( { \sqrt{x}) }^{2} = {(10)}^{2}$

X= 100

8.)

$( {x + 1)}^{2} = 81$

$(x + 1) = \sqrt{81}$

$x + 1 = \sqrt{ {9}^{2} }$

$x + 1 = 9$

$x = 9 - 1$

X=8

Hope it helps...