1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vikki [24]
3 years ago
12

Identify each of the following reactions as balanced or unbalanced. CH4+ 2O2 → CO2 + 2H2O: CaCl2+ 2AgNO3 → Ca(NO3)2 + 2AgCl: 3Fe

3O4 + 4Al → 9Fe + 4Al2O3:
Chemistry
2 answers:
kap26 [50]3 years ago
8 0

1) The answer is: chemical reaction is balanced.

Chemical reaction: CH₄ + O₂ → CO₂ + H₂O.

Oxidation reaction: C⁻⁴ → C⁺⁴ + 8e⁻.

Reduction reaction: O₂ + 4e⁻ → 2O⁻² /×2; 2O₂ + 8e⁻ → 4O⁻².

Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.

Carbon change oxidation number from -4 to +4 (oxidation) and oxygen change oxidation number from 0 to -2 (reduction).

2) The answer is: chemical reaction is balanced.

Balanced chemical reaction: CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl.

Number of atoms must be the same on left and right side of balanced chemical reaction according to the law of conservation of mass or principle of mass conservation.

There are two chlorine atoms (Cl), one calcium atom (Ca), six oxygen atoms (O), one nitrogen atoms (N) and two silver atoms (Ag) in this balanced chemical reaction.

3) The answer is: chemical reaction is unbalanced.

Chemical reaction: 3Fe₃O₄ + 4Al → 9Fe + 4Al₂O₃.

Number of aluminium atoms (Al) is unbalanced. There are four aluminium atoms on the left and eight aluminium atoms on right side of chemical reaction.

Balanced chemical reaction: 3Fe₃O₄ + 8Al → 9Fe + 4Al₂O₃.

According to principle of mass conservation, number of atoms must be equal on both side of chemical reaction.

ICE Princess25 [194]3 years ago
4 0

1) The answer is: chemical reaction is balanced.

2) The answer is: chemical reaction is balanced.

3) The answer is: chemical reaction is unbalanced.

You might be interested in
Which would have the LEAST gravitational potential energy (GPE)? A ball sitting on the ground An airplane flying 30,000 feet abo
ryzh [129]

Answer:

(A) A ball sitting on the ground

Explanation:

8 0
3 years ago
A solution contains 0.0440 M Ca2 and 0.0940 M Ag. If solid Na3PO4 is added to this mixture, which of the phosphate species would
Olenka [21]

Answer:

C. Ca_3(PO_4)_2  will precipitate out first

the percentage of Ca^{2+}remaining =  12.86%

Explanation:

Given that:

A solution contains:

[Ca^{2+}] = 0.0440 \ M

[Ag^+] = 0.0940 \ M

From the list of options , Let find the dissociation of Ag_3PO_4

Ag_3PO_4 \to Ag^{3+} + PO_4^{3-}

where;

Solubility product constant Ksp of Ag_3PO_4 is 8.89 \times 10^{-17}

Thus;

Ksp = [Ag^+]^3[PO_4^{3-}]

replacing the known values in order to determine the unknown ; we have :

8.89 \times 10 ^{-17}  = (0.0940)^3[PO_4^{3-}]

\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}  = [PO_4^{3-}]

[PO_4^{3-}] =\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}

[PO_4^{3-}] =1.07 \times 10^{-13}

The dissociation  of Ca_3(PO_4)_2

The solubility product constant of Ca_3(PO_4)_2  is 2.07 \times 10^{-32}

The dissociation of Ca_3(PO_4)_2   is :

Ca_3(PO_4)_2 \to 3Ca^{2+} + 2 PO_{4}^{3-}

Thus;

Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2

2.07 \times 10^{-33} = (0.0440)^3  [PO_4^{3-}]^2

\dfrac{2.07 \times 10^{-33} }{(0.0440)^3}=   [PO_4^{3-}]^2

[PO_4^{3-}]^2 = \dfrac{2.07 \times 10^{-33} }{(0.0440)^3}

[PO_4^{3-}]^2 = 2.43 \times 10^{-29}

[PO_4^{3-}] = \sqrt{2.43 \times 10^{-29}

[PO_4^{3-}] =4.93 \times 10^{-15}

Thus; the phosphate anion needed for precipitation is smaller i.e 4.93 \times 10^{-15} in Ca_3(PO_4)_2 than  in  Ag_3PO_4  1.07 \times 10^{-13}

Therefore:

Ca_3(PO_4)_2  will precipitate out first

To determine the concentration of [Ca^+] when  the second cation starts to precipitate ; we have :

Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2

2.07 \times 10^{-33}  = [Ca^{2+}]^3 (1.07 \times 10^{-13})^2

[Ca^{2+}]^3 =  \dfrac{2.07 \times 10^{-33} }{(1.07 \times 10^{-13})^2}

[Ca^{2+}]^3 =1.808 \times 10^{-7}

[Ca^{2+}] =\sqrt[3]{1.808 \times 10^{-7}}

[Ca^{2+}] =0.00566

This implies that when the second  cation starts to precipitate ; the  concentration of [Ca^{2+}] in the solution is  0.00566

Therefore;

the percentage of Ca^{2+}  remaining = concentration remaining/initial concentration × 100%

the percentage of Ca^{2+} remaining = 0.00566/0.0440  × 100%

the percentage of Ca^{2+} remaining = 0.1286 × 100%

the percentage of Ca^{2+}remaining =  12.86%

5 0
3 years ago
How would you test a colorless crystalline compound to determine if it was a hydrate?
Cloud [144]

A hydrate is a substance where in it contains water and other constituent elements. To know whether if that compound was a hydrate,you should record its mass, then put it in a test tube and heat it with a Bunsen burner. If the compound is a hydrate, the water in the compound will discharge in the form of water vapor. At the next 5-10 minutes, remove it in the test tube and weigh it up again. If the mass is now fewer, that means that there was water existing that has now evaporated, and the compound was a hydrate.

6 0
3 years ago
isotopes of an element have the same number of protons but a different number of neutrons below u will see the nucleus of four d
dexar [7]
What is your question? Its not clear
3 0
3 years ago
Helppppp asaapppppp plzzzzzz
Gala2k [10]

Answer:

Alright the very first thing you need to do is balance the equation:

2HCl + Na2CO3 -----> 2NaCl + CO2 + H2O

Now we need to find the limiting reactant by converting the volume to moles of both HCl and Na2CO3.

Volume x Concentration/molarity = moles

0.235L x 0.6 M = 0.141 moles / molar ratio of 2 = 0.0705 moles of HCl

0.094L x 0.75 M = 0.0705 moles /molar ratio of 1  = 0.0705 moles of Na2CO3

Since both of the moles are equal, it means the entire reaction is complete (while the identification of limiting reactant may seem like an unnecessary step, it's quite essential in stoichiometry, so keep an eye out) and there is no excess of any reactant.

Now we know that the product we want to calculate is aqueous so, following the law of conservation of mass, we should add both volumes together to calculate how much volume we could get for NaCl.

0.235 + 0.094 = 0.329L of NaCl

Now we apply the C1V1 = C2V2 equation using the concentration and volume of Na2CO3 because it's molar ratio is one to one to NaCl (You can also use HCL, but you have to divide their moles by 2 for the molar ratio)  and the volume we just calculated for NaCl.

(0.75M) x (0.094L) = C2 x (0.329L)

Rearrange equation to solve for C2:

<u>(0.75M) x (0.094L)</u>  =  C2

    (0.329L)

C2 = 0.214 M (Rounded)

<u>When the reaction is finished, the NaCl solution will have a molarity concentration of 0.214 M.</u>

<u></u>

<u />

7 0
2 years ago
Other questions:
  • Why are some rocks more easily weathered that others
    14·1 answer
  • Which of the following best represents potential energy being converted to kinetic energy
    11·1 answer
  • 4.05 kg + 567.95 g + 100.1 g add the correct value using the correct sig figs and or least precise degree of precision. When i d
    9·1 answer
  • As the ball falls, its energy will decrease and its energy will increase
    9·1 answer
  • One mole of Ca is equal to how many atoms​
    15·1 answer
  • Determine the ph of a 0.227 m c5h5n solution at 25°c. the kb of c5h5n is 1.7 × 10-9.
    14·2 answers
  • A liquid that occupies a volume of 9.0 L has a mass of 7.2 kg. What is the density of the liquid in kg/L ?
    10·2 answers
  • What happens during the cell cycle
    15·1 answer
  • Giving brainiest i need help with number 3
    15·1 answer
  • The area in which an object experiences a noncontact force is called a field. Examples of fields include electrical fields, magn
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!