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3 years ago

An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?

Physics

1 answer:

Morgarella [4.7K]3 years ago

5 0

<h3>Answer:</h3>

5.5 N

<h3>Explanation:</h3>

<u>We are given;</u>

Real weight of an object in air as 10 N
Apparent weight in water as 7 N
Relative density of a liquid is 1.5

We need to calculate the apparent weight when in liquid .

First we calculate upthrust

Upthrust = Real weight - Apparent weight

= 10 N - 7 N

= 3 N

Then calculate the upthrust in the liquid.

we need to know that;

Relative density of a liquid = Upthrust in liquid/Upthrust in water

Therefore;

1.5 = U ÷ 3 N

Upthrust in liquid = 3 N × 1.5

= 4.5 N

Therefore, the upthrust of the object in the liquid is 4.5 N

But, Upthrust = Real weight - Apparent weight

Therefore;

Apparent weight in Liquid = Real weight - Upthrust

= 10 N - 4.5 N

= 5.5 N

Thus, the weight when the object is immersed in the liquid is 5.5 N

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An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?​

An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?