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Elanso [62]
3 years ago
13

An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?​

Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0
<h3>Answer:</h3>

5.5 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Real weight of an object in air as 10 N
  • Apparent weight in water as 7 N
  • Relative density of a liquid is 1.5

We need to calculate the apparent weight when in liquid .

  • First we calculate upthrust

Upthrust = Real weight - Apparent weight

              = 10 N - 7 N

               = 3 N

  • Then calculate the upthrust in the liquid.

we need to know that;

Relative density of a liquid  = Upthrust in liquid/Upthrust in water

Therefore;

1.5 = U ÷ 3 N

Upthrust in liquid = 3 N × 1.5

                             = 4.5 N

  • Therefore, the upthrust of the object in the liquid is 4.5 N

But, Upthrust = Real weight - Apparent weight

Therefore;

Apparent weight in Liquid = Real weight - Upthrust

                                           = 10 N - 4.5 N

                                           = 5.5 N

Thus, the weight when the object is immersed in the liquid is 5.5 N

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Answer:

The correct answer is D.

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Explanation:

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Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.

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Explanation:

Just read the story :)

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If the electric field of an electromagnetic wave is in the x-direction and the magnetic field of the wave is in the y-direction,
Ulleksa [173]

Answer:

Positive z-direction

Explanation:

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Therefore, the correct option will be positive z-direction.

3 0
2 years ago
Two trains on separate tracks move toward each other. Train 1 has a speed of 145 km/h; train 2, a speed of 72.0 km/h. Train 2 bl
tekilochka [14]

Answer:

Therefore,

The frequency heard by the engineer on train 1

f_{o}=603\ Hz

Explanation:

Given:

Two trains on separate tracks move toward each other

For Train 1 Velocity of the observer,

v_{o}=145\ km/h=145\times \dfrac{1000}{3600}=40.28\ m/s

For Train 2 Velocity of the Source,

v_{s}=90\ km/h=90\times \dfrac{1000}{3600}=25\ m/s

Frequency of Source,

f_{s}=500\ Hz

To Find:

Frequency of Observer,

f_{o}=?  (frequency heard by the engineer on train 1)

Solution:

Here we can use the Doppler effect equation to calculate both the velocity of the source v_{s} and observer v_{o}, the original frequency of the sound waves f_{s} and the observed frequency of the sound waves f_{o},

The Equation is

f_{o}=f_{s}(\dfrac{v+v_{o}}{v -v_{s}})

Where,

v = velocity of sound in air = 343 m/s

Substituting the values we get

f_{o}=500(\dfrac{343+40.28}{343 -25})=500\times 1.205=602.64\approx 603\ Hz

Therefore,

The frequency heard by the engineer on train 1

f_{o}=603\ Hz

7 0
3 years ago
Technician A says that shop air pressure usually ranges from 100–150 psi. Technician B says shop air pressure is around 300 psi.
mr Goodwill [35]

Answer:

technician A.

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5 0
3 years ago
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