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Elanso [62]
3 years ago
13

An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?​

Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0
<h3>Answer:</h3>

5.5 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Real weight of an object in air as 10 N
  • Apparent weight in water as 7 N
  • Relative density of a liquid is 1.5

We need to calculate the apparent weight when in liquid .

  • First we calculate upthrust

Upthrust = Real weight - Apparent weight

              = 10 N - 7 N

               = 3 N

  • Then calculate the upthrust in the liquid.

we need to know that;

Relative density of a liquid  = Upthrust in liquid/Upthrust in water

Therefore;

1.5 = U ÷ 3 N

Upthrust in liquid = 3 N × 1.5

                             = 4.5 N

  • Therefore, the upthrust of the object in the liquid is 4.5 N

But, Upthrust = Real weight - Apparent weight

Therefore;

Apparent weight in Liquid = Real weight - Upthrust

                                           = 10 N - 4.5 N

                                           = 5.5 N

Thus, the weight when the object is immersed in the liquid is 5.5 N

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We will convert the 1dm3 in terms of cm3 as follows:

1dm^3 = (10 cm)^3
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The mass of platinum is equal to 900 lb. 
Then we will convert the mass in terms of grams as follows:
1 lb = 453.6 g
900 = 900 x 453.6 g
= 408240 g

Then density of platinum is equal to 21.4 g/cm^3 
We will calculate the volume of platinum in mass 408240 g as follows:
Volume of platinum = mass of platinum / density of platinum
= 408240 g / 21.4 g/cm^3 
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The total volume of platinum is 19076.6 cm^3
The volume of platinum in 1 L bar is 1000cm^3
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Number of bars = volume of platinum available / volume of platinum required in 1 L bar
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4 0
3 years ago
A wave of wavelength 0.3 m travels 900 m in 3.0 s. Calculate its frequency.
zzz [600]

Answer:

1000 Hz

Explanation:

<em>The frequency would be 1000 Hz.</em>

The frequency, wavelength, and speed of a wave are related by the equation:

<em>v = fλ ..................(1)</em>

where v = speed of the wave, f = frequency of the wave, and λ = wavelength of the wave.

Making f the subject of the formula:

<em>f = v/λ.........................(2)</em>

Also, speed (v) = distance/time.

From the question, distance = 900 m, time = 3.0 s

Hence, v = 900/3.0 = 300 m/s

Substitute v = 300 and λ = 0.3  into equation (2):

f = 300/0.3 = 1000 Hz

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What is the kinetic energy of a bike with a mass of 24 kg traveling at 3 m/s?
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Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h
padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

v=\sqrt{\frac{2GM}{R}}

where G is the universal gravitational constant, M is the mass of the asteroid and R is the radius

and since the scape velocity is 50m/s:

50m/s=\sqrt{\frac{2GM}{R}}

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: 2M

and the radius is: 2R

inserting these values into the formula for escape velocity:

v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }

and we have found that 50m/s=\sqrt{\frac{2GM}{R}}, so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

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