<h3>
Answer:</h3>
5.5 N
<h3>
Explanation:</h3>
<u>We are given;</u>
- Real weight of an object in air as 10 N
- Apparent weight in water as 7 N
- Relative density of a liquid is 1.5
We need to calculate the apparent weight when in liquid .
- First we calculate upthrust
Upthrust = Real weight - Apparent weight
= 10 N - 7 N
= 3 N
- Then calculate the upthrust in the liquid.
we need to know that;
Relative density of a liquid = Upthrust in liquid/Upthrust in water
Therefore;
1.5 = U ÷ 3 N
Upthrust in liquid = 3 N × 1.5
= 4.5 N
- Therefore, the upthrust of the object in the liquid is 4.5 N
But, Upthrust = Real weight - Apparent weight
Therefore;
Apparent weight in Liquid = Real weight - Upthrust
= 10 N - 4.5 N
= 5.5 N
Thus, the weight when the object is immersed in the liquid is 5.5 N
