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Elanso [62]
3 years ago
13

An object weighs 10N in air and 70N in water .What is it's weight when immersed in a liquid of relative density 1.5?​

Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0
<h3>Answer:</h3>

5.5 N

<h3>Explanation:</h3>

<u>We are given;</u>

  • Real weight of an object in air as 10 N
  • Apparent weight in water as 7 N
  • Relative density of a liquid is 1.5

We need to calculate the apparent weight when in liquid .

  • First we calculate upthrust

Upthrust = Real weight - Apparent weight

              = 10 N - 7 N

               = 3 N

  • Then calculate the upthrust in the liquid.

we need to know that;

Relative density of a liquid  = Upthrust in liquid/Upthrust in water

Therefore;

1.5 = U ÷ 3 N

Upthrust in liquid = 3 N × 1.5

                             = 4.5 N

  • Therefore, the upthrust of the object in the liquid is 4.5 N

But, Upthrust = Real weight - Apparent weight

Therefore;

Apparent weight in Liquid = Real weight - Upthrust

                                           = 10 N - 4.5 N

                                           = 5.5 N

Thus, the weight when the object is immersed in the liquid is 5.5 N

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Explanation:

Hi there!

Please, see the attached figure for a graphic representation of the forces acting on the sled after the bobsleder jumped in.

In the vertical direction, the acting forces are the normal force (N) and the weight of the sled plus the bobsledder (W).

Since the sled is not being accelerated in the vertical direction, the sum of forces in that direction is zero:

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Solving for "a":

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