The energy of photon in kJ/mol is 329kJ/mol.
Wavelength of radiation is 370nm. The frequency of given wavelength is
ν = c / λ
ν = 3×10^8 / 370×10^-9
ν = 8.11 × 10^14 s^-1
Now the energy of photon is:
E = hν
E = 6.63×10^-34 J.s/photon × 8.11×10^14s^-1
E = 5.41× 10^-19 J/photon
To find in mole
E = 5.41× 10^-19 × 6.022×10^23
E = 3.29 ×10^ 5 J/mol
So, the energy of mole of photon is equal to 329 kJ/mol.
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Answer:
1.19 m/s²
Explanation:
The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so
f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀ (1)
Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²
Equating (1) and (2) we ave
2(√mg/μ)/f = T²g/4π²
Making g subject of the formula
g = 2π√(2√(m/μ)/f)/T
The period T = 316 s/100 = 3.16 s
Substituting the other values into , we have
g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16
g = 2π√(2 × 35.877/200 Hz)/3.16
g = 2π√(71.753/200 Hz)/3.16
g = 2π√(0.358)/3.16
g = 2π × 0.599/3.16
g = 1.19 m/s²
Newton's second law of motion states the following:
In which
is the force,
is the mass, and
is the acceleration of the object.
So, the answer is B.
Answer:
1. OK the
1. The horizontal axis of a osclloscope is generally TIME axis.
2. given T =25 micro second
That is = 25E-6 s
Then We f = (1/T) .
So f = 1/(25 x 10^-6) = 40000 Hz =
40 KHz.
3. First Band will be Yellow
Second Band will be Violet
Third Band will be Red
And
Fourth Band will be Gold
Thus, the value of the resistance = (47 x 100)plus or minus 5%
= (4700 plus or minua5%) ohm
the range of the acceptable value of the resistance will now be
= 4465 ohm to 4935 ohm
(4)
The level provided by the wall outlet = 120 x √2 = 169.68 V
The √2 is because the multimeter measures RMS voltage rather than peak voltage and
RMS Voltage is = √2 x peak voltage
