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gayaneshka [121]
3 years ago
9

Từ độ cao 100 m người ta thả một vật thẳng đứng xuống với v = 10 m/s, g = 10 m/s2 . a. Sau bao lâu vật chạm đất. b. Tính vận tốc

của vật lúc vừa chạm đất.
Physics
2 answers:
kifflom [539]3 years ago
6 0

Câu 1. Một ôtô đang chạy với vận tốc 54km/h thì tài xế hãm phanh, sau 10 giây tốc độ của ôtô là 36km/h.

a) Tìm gia tốc của ôtô?

b) Tìm quãng đường ôtô đi được trong thời gian hãm phanh?

c) Tinh vận tốc của ôtô sau 16 giây kể từ lúc hãm phanh?

Câu 2. Từ độ cao 80m so với mặt đất, thả một vật rơi tự do. Lấy g = 10 m/s2

a) Tính thời gian vật rơi?

b) Tính vận tốc của vật khi chạm đất?

Câu 3. Một vật có khối lượng 500g đang nằm yên, chịu tác dụng một lục 1,2 N, vật chuyển động nhanh dần

đều.

a) Tìm gia tốc của vật?

b) Tìm quãng đường mà vật đi được sau 1 phút?

c) Tính vật tốc của vật sau 30s kể từ lúc bắt đầu chuyển động ?

d) Sau bao lâu kể từ lúc bắt đầu chuyển động, vật có vận tốc 72km/h?

Bas_tet [7]3 years ago
3 0

Answer:

10 points dapat yawa aman daw gud

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A charge of Q is fixed in space. A second charge of q was first placed at a distance r1 away from Q. Then it was moved along a s
topjm [15]

Answer:

\Delta U = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

Explanation:

The electrostatic potential energy is given by the following formula

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Now, we will apply this formula to both cases:

U_1 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_1^2}\\U_2 = \frac{1}{4\pi\epsilon_0}\frac{Qq}{r_2^2}

So, the change in the potential energy is

\Delta U = U_2 - U_1 = \frac{Qq}{4\pi\epsilon_0}(\frac{1}{r_2^2}-\frac{1}{r_1^2})

7 0
3 years ago
A ball is thrown vertically downward at 10 m/s. what is it’s speed 1s and 2s later
soldi70 [24.7K]

Answer:

20 m/s

30 m/s

Explanation:

Given:

v₀ = -10 m/s

a = -9.8 m/s²

When t = 1 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (1 s)

v = -19.8 m/s

When t = 2 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (2 s)

v = -29.6 m/s

Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.

3 0
3 years ago
A soap bubble, when illuminated at normal incidence with light of 463 nm, appears to be especially reflective. If the index of r
Sedbober [7]

Answer:

the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

Explanation:

Given the data in the question;

wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m

Index of refraction; n = 1.35

Now, the thinnest thickness of the soap film can be determined from the following expression;

t_{min = ( λ / 4n )

so we simply substitute in our given values;

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = ( 463 × 10⁻⁹ m ) / 5.4

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = 8.574 × 10⁻⁸ m

t_{min = 85.74 × 10⁻⁹ m

t_{min = 85.74 nm

Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

5 0
3 years ago
Technician A says that vehicle-to-vehicle communication results in fewer traffic collisions. Technician B says there are concern
Leto [7]

Answer:

Option C. Both technicians A and B are correct

Explanation:

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Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.

By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users

4 0
3 years ago
Which describes the relationship between photon energy and frequency?
nasty-shy [4]
E = hf
E : photon energy
h : Plank's constant 6.63×10^-34
f : frequency

Hope it helped!
8 0
3 years ago
Read 2 more answers
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