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Simora [160]
2 years ago
10

(a) At a certain instant, a particle-like object is acted on by a force F = (5.0 N) i hat - (2.0 N) j + (8.0 N) k while the obje

ct's velocity is v = - (2.0 m/s) i hat + (4.0 m/s) k. What is the instantaneous rate at which the force does work on the object?
Physics
1 answer:
Ksenya-84 [330]2 years ago
7 0

Answer:

Power, P = 22 W

Explanation:

It is given that,

Force acting on the object, F=5i-2j+8k

Velocity of the object, v=-2i+4k  

To Find,

The rate at which the force does work on the object

Solve,

The rate at which the force does work on the object is called its power. Its formula is given by :

P=\dfrac{W}{t}

P=\dfrac{F.d}{t}

P=F\times v

P=(5i-2j+8k)\times (-2i+4k)

P=-10+0+32=22\ W

So, the force work on the object at the rate of 22 watts

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A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
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Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

3x=(1/2)a(t')^2

Solving for t':

t'=√(6x/a)

Now, the velocity of the motorcycle as a function of time is:

v(t)=a*t

Evaluating at t=t'

v(t')=a*√(6x/a)=√(6*x*a)

Which is the final velocity

Have a nice day!

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3 years ago
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Oksana_A [137]
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3 years ago
Which players are usually the tallest on their team, and stay close to the basket so they can shoot and rebound the ball?
alexdok [17]

Answer:

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A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will
Aleks [24]

Answer:

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Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.

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