Answer:
533.92 m/s
Explanation:
The root-mean-square speed of a gas is given by v = √(3RT/M)
R = molar gas constant = 8.3145 J/mol-K
T = Temperature = 320 K
M = Molar mass of Nitrogen in kg/mol = 2 × 14 × 10⁻³ kg/mol = 28 × 10⁻³ kg/mol
v = √(3RT/M) = √(3 × 8.3145 J/mol-K × 320 K/28 × 10⁻³ kg/mol) = √7981920/28 = √285.068.57 = 533.92 m/s
So, there should be two forces acting on the refrigerator: the applied force and the friction force.
The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.
We have an applied force of 400 N to the right, this means that:
<span>The magnitude of the net force is 400, directed to the right.</span>
<span>When two hydrogen atoms bond, the positive nucleus of one atom attracts the electrons of both the atoms since the electrons are shared between the two atoms now.</span>
Answer: h = 0.30 m
Explanation:
A person jumping from height h would possess potential energy = m g h
which will convert completely into kinetic energy as person hits the ground. Now, the maximum energy absorbed by the person can be = 200 J
m = 67 kg
g = 9.8 m/s²
⇒ m g h = 200 J
⇒ h = 200 J / (67 kg × 9.8 m/s²) = 0.30 m
Hence, a person can land safely on both legs without breaking them from a height of 0.30 m only.
Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:
(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>
where <em>v</em> is the velocity of the system. Solve for <em>v</em> :
<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)
<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s
