Ask question

Ask question

All categories

3 years ago

14

How do u write these numbers from greatest to least

2 answers:

ycow [4]3 years ago

8 0

I don't know what numbers you want me to order from great to least, but a example is 1,510, 964, 478, 219, 96, 57, 35, 10, 9, 4, 3,

m_a_m_a [10]3 years ago

4 0

887.304,887.043,878.403

You might be interested in

Chang knows one

larisa86 [58]

9514 1404 393

Answer:

(d) 8 cm and 9 cm

Step-by-step explanation:

The sum of the other two side lengths must <em>exceed</em> 13 cm for a triangle to be possible.

8 cm and 9 cm

5 0

3 years ago

Read 2 more answers

The work of a student to find the dimensions of a rectangle of area 6 + 8x and width 2 is shown below:

tatiyna

Answer:
Step 2; 2(3) = 2(4x)

5 0

3 years ago

Read 2 more answers

How do you solve this help

vfiekz [6]

Answer:

arc PST = 254°

Step-by-step explanation:

arc QPT = 180° because it is a diameter

arc PQ = 74°

arc PT = 180° - 74° = 106°

arc PST = 360° - 106° = 254°

5 0

3 years ago

Sold the equation. Round to the nearest hundredth. <br><br>17 · <img src="https://tex.z-dn.net/?f=1.8%5E%7B-x%2B7%7D%20%3D%205"

svetlana [45]

Answer:

Final answer is approx x=4.26.

Step-by-step explanation:

Given equation is $1.8^{-x+7} = 5$

Now we need to solve equation $1.8^{-x+7} = 5$ and round to the nearest hundredth.

$1.8^{-x+7} = 5$

$\log(1.8^{-x+7}) = \log(5)$

$(-x+7)\log(1.8) = \log(5)$

$(-x+7) = \frac{\log(5)}{\log(1.8)}$

$(-x+7) = \frac{0.698970004336}{0.255272505103}$

$-x+7 = 2.73813274192$

$-x = 2.73813274192-7$

$-x =−4.26186725808$

$x =4.26186725808$

Round to the nearest hundredth.

Hence final answer is approx x=4.26.

4 0

3 years ago

The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a

Evgesh-ka [11]

The complete question is as follows.

The equation a = $\frac{1}{2}(b_1 + b_2 )h$ can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, $b_1$ and $b_2$ . Which are equivalent equations?

(a) $\frac{2a}{h} - b_2 = b_1$

(b) $\frac{a}{2h} - b_2 = b_1$

(c) $\frac{2a - b_2}{h}$ = $b_1$

(d) $\frac{2a}{b_1 + b_2} = h$

(e) $\frac{a}{2(b_1 + b_2)}$ = h

Answer: (a) $\frac{2a}{h} - b_2 = b_1$ ; (d) $\frac{2a}{b_1 + b_2} = h$ ;

Step-by-step explanation: To determine $b_1$ :

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = ( $b_1 + b_2$ )h

$\frac{2a}{h} = b_1 + b_2$

$\frac{2a}{h} - b_2 = b_1$

To determine h:

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{(b_1 + b_2)}$ = h

To determine $b_2$

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{h} = (b_1 + b_2)$

$\frac{2a}{h} - b_1 = b_2$

Checking the alternatives, you have that $\frac{2a}{h} - b_2 = b_1$ and $\frac{2a}{(b_1 + b_2)}$ = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0

3 years ago