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ale4655 [162]
4 years ago
10

Forces that are equal in strength and opposite in direction are

Chemistry
2 answers:
777dan777 [17]4 years ago
8 0

Answer:

Forces that are equal in strength and opposite in direction are <u><em>balanced forces.</em></u>

Explanation:

The force is a vector magnitude by which a body can deform, modify its speed or get into motion overcoming a state of inertia and immobility. In other words, it is called force to any cause (action, effort or influence) that can alter the state of motion or rest of any body or deform it.

The unit of measure of force is Newton, whose symbol is N.

As mentioned, force is a vector magnitude, so it has four fundamental properties that are: intensity, direction, direction and point of application (surface where force is applied).

The forces are said to be balanced when the net force on the object is zero (that is, the result of the sum of all forces is zero) and the forces are not balanced when the net force is non-zero (that is, the result of the sum of all forces is not zero).

In other words, for the forces to be balanced all the forces acting on a body must cancel each other out, so that the resulting force or net force is zero. In order to cancel or add zero, the forces must be of equal magnitude but opposite directions. This causes that if the forces acting on an object are balanced, the state of motion of the body does not change. That is to say that if the body is at rest, it remains in this state. And if the body is moving, it will continue moving with constant speed.

<u><em>Forces that are equal in strength and opposite in direction are balanced forces.</em></u>

Sedaia [141]4 years ago
5 0

Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion. When you add equal forces in opposite direction, the net force is zero.

hope this helped, please mark brainliest :)

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The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D
dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

                                             = 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free   energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so,  0 = ΔH - T (Δ S)

      T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

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4 years ago
What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

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ki77a [65]

Answer:

(1)There are 1.5 moles of water in a 27 gram sample of water. The molar mass of water is 18.02 gmol g m o l .(2)

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What is the mass (g) of 0.25mols of NaCl?

What you need for these equations are a calculator, periodic table and the following equation:

Mass (g) = Mr x Moles (important equation to remember)

In this case we already know the moles as it's in the question, 0.25 moles.

to find the Mr, you need to look at your periodic table. Find the relative atomic mass of Na and Cl and add the two numbers together.

Na = 22.99

Cl = 35.45

NaCl = 58.4

Now just put all of the numbers into the equation.

0.25 x 58.4 = 14.6g

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