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maksim [4K]
3 years ago
11

A compound consists of only one type of element?

Chemistry
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

A compound can easily be split up into its different elements.

Explanation:

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An element has 3 electrons, 3 protons and 4 neutrons. What will be its atomic number and mass number? (​
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its atomic number will be 3 and it's mass number will be 7. it is lithium

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Is baking soda is dissolved in vinegar and bubbles appear a chemical change?
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How to separate milk and water​
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Milk is a mixture of protein and fat and sugars suspended in water. Water is mixed with milk in order to make it more dilute. Once the water is mixed with milk, it is not easy to separate the milk from water. What is possible is to concentrate the milk by evaporating a part of the water contained in milk

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4 years ago
Anabolic steroids are sometimes used illegally by athletes to increase muscle strength. A forensic chemist analyzes some tablets
11111nata11111 [884]

Answer:

The empirical formula is = C_{10}H_{14}O

The formula of steroid = C_{20}H_{28}O_2

Explanation:

Mass of water obtained = 1.007 g

Molar mass of water = 18 g/mol

Moles of H_2O = 1.007 g /18 g/mol = 0.0559 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 0.0559 = 0.1119 moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 0.1119 x 1.008 = 0.1128 g

Mass of carbon dioxide obtained = 3.516 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of CO_2 = 3.516 g  /44.01 g/mol = 0.0799 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 0.0799 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 0.0799 x 12.0107 = 0.9595 g

Given that the steroids only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C  - Mass of H

Mass of the sample = 1.200 g

Mass of O in sample = 1.200 - 0.9595 - 0.1128 = 0.1277 g  

Molar mass of O = 15.999 g/mol

Moles of O  = 0.1277 / 15.999  = 0.00798 moles

Taking the simplest ratio for H, O and C as:

0.1119 : 0.00798 : 0.0799

= 14 : 1 : 10

The empirical formula is = C_{10}H_{14}O

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 10×12 + 14×1 + 16= 150 g/mol

Molar mass = 300.42 g/mol

So,  

Molecular mass = n × Empirical mass

300.42 = n × 150

⇒ n = 2

The formula of steroid = C_{20}H_{28}O_2

6 0
4 years ago
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