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astraxan [27]
4 years ago
6

2

Mathematics
1 answer:
Snezhnost [94]4 years ago
7 0

An additive inverse of a number (x) is a number which when added to x results in being 0.

The given problem is -3 - (-6)

The additive inverse of -6 is 6

-3 -(-6) = -3 + 6 = 3

Communities property: 6-3 = 3

The answer is:

Because -3+6 is an equivalent expression, the answer is 3

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The perimeter of the window of the camper shell is 130 in. Find the length of one of the shorter sides of the window.
erik [133]

You can't deduce the length of a side from the perimeters of a rectangle.

Say that s and S are, respectively, the short and long side of the rectangle.

So, we know that

2s+2S=130 \iff 2(s+S)=130 \iff s+S=65

But we can't solve exactly for s nor for S, unless more information is given.

7 0
3 years ago
X² +12x+27 = 0<br><br> Find the roots of each equation by factoring
Setler79 [48]

Answer:

x = -9, -3

Step-by-step explanation:

{x }^{2} + 12x + 27 = 0

(x + 3)(x + 9) = 0

x = -3, -9

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2 years ago
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B) Write down an expression for the nth term of the following sequence.
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Answer:

32,41,51,62,74,87,101

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3 years ago
Is it possible to draw a triangle with sides 150cm, 10 cm, and 10cm
Oliga [24]
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3 years ago
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A machine that manufactures automobile pistons is estimated to produce a defective piston 1% of the time. Suppose that this esti
GenaCL600 [577]

Answer:

Mean: 0.9 pistons

Standard deviation: 0.944 pistons

Step-by-step explanation:

Either a piston is defective, or it is not. This means that for either piston, there can only be two outcomes. This means that we can solve this problem by the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and each trial can only have two outcomes, with probabilities \pi and 1 - \pi.

For an experiment with n repeated trials and a probability of success \pi, we have that:

The mean is: \mu_{x} = n*\pi

The standard deviation is: \sigma_{x} = \sqrt{n*\pi*(1-\pi)}

In this problem

There are 90 pistons, so n = 90.

There is a 1% probability that a piston is defective, so \pi = 0.01.

Estimate the number of pistons in the sample that are defective by giving the mean of the relevant distribution:

\mu_{x} = n*\pi = 90(0.01) = 0.9

Quantify the uncertainty of your estimate by giving the standard deviation of the distribution.

\sigma_{x} = \sqrt{n*\pi*(1-\pi)} = 0.944

6 0
3 years ago
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