Electrodes used in arc welding processes are classified as consumable or non- consumable. Filler metal is always added when cons
1 answer:
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Answer:
The width of the slit is 0.167 mm
Explanation:
Wavelength of light,
Distance from screen to slit, D = 88.5 cm = 0.885 m
The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m
We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :
where
a = width of the slit
a = 0.000167 m
a = 0.167 mm
So, the width of the slit is 0.167 mm. Hence, this is the required solution.
Answer:
kinetic energy is 3.68 × J
speed of these electrons is 0.5565 c
Explanation:
Given data
voltage difference = 230 kV
to find out
kinetic energy and speed of these electrons
solution
we know kinetic energy formula that is
kinetic energy = qv
kinetic energy = 1.6 × × 230 ×
kinetic energy = 3.68 × J
and
speed of electron that is
kinetic energy = m1c² - m2 c²
here m1 = m / √(1-v/c)²
so
KE/mc² = ( 1 / √(1-(v/c)² ) - 1
put value here
3.68 × / (3× 10^8)²×9.11×
= ( 1 / √(1-v/c)² ) - 1
0.448835223 = ( 1 / √(1-(v/c)² ) - 1
( 1 / √(1-(v/c)² ) = 0.448835223 + 1 = 1.448835223
√(1-(v/c)² = 1 / 1.448835223 = 0.6902096
(v/c)² = 1 - 0.6902096 = 0.309790
v = 0.5565 c
speed of these electrons is 0.5565 c