Answer:
The decibel of the remaining pigs is 51.5 dB.
Explanation:
Decibel (dB) is a unit of measure of the intensity of a given sound.
Number of pigs = 199, noise level = 74.3 dB.
Given that the intensity (I) of the sound from the pen is proportional to the number of pigs (N), thus:
I
N
I = kN
where k is the constant of proportionality.
⇒ k = 
= 
k = 0.3734
When 61 numbers of pigs were removed, the number of remaining pigs (N) squealing at their original level is 138.
Thus, the becibel level (I) of the remaining pigs can be determined by:
I = kN
= 0.3734 × 138
= 51.53 dB
The becibel level (I) of the remaining pigs is 51.53 dB.
Answer:
B. changing shape and changing volume
Explanation:
*no definite shape (takes the shape of its container)
*no definite volume
Answer:
The speed is equals to 22.49 m/s
Explanation:
Given Data:

Required:
Speed of Traverse wave = c =?
Solution:
As we know that

Now the equation for speed of traverse wave is calculated through:

=
Substituting the values

=22.49 m/s
Answer:
1.6 s
Explanation:
To find the time in which the potential difference of the inductor reaches 24V you use the following formula:

V_o: initial voltage = 60V
R: resistance = 24-Ω
L: inductance = 42H
V_L: final voltage = 24 V
You first use properties of the logarithms to get time t, next, replace the values of the parameter:

hence, after 1.6s the inductor will have a potential difference of 24V