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Nimfa-mama [501]
3 years ago
5

Lithium

Physics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:d

Explanation:

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An object moving with a speed v0 collides head-on with a second object initially at rest. A student assumes the collision is ela
AleksAgata [21]

Answer:B

Explanation:

It is given that the first collision is elastic so we can conserve momentum as well as the kinetic energy of the system.

The value of the coefficient of restitution is equal to one for an elastic collision. An elastic collision is also called a perfectly Elastic collision.

A perfectly inelastic collision is one in which there is the loss of kinetic energy and some of the kinetic energy is converted into another form of energy, for example, internal energy.

although momentum is conserved in Inelastic collision kinetic energy is not conserved.    

6 0
4 years ago
A jet stream generally diverges above a low-pressure (warm) center. However, at Earth's surface, air converges at a low-pressure
Gemiola [76]

The correct answer is that the surface winds will get stronger.

6 0
3 years ago
What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second?
Alexus [3.1K]

Given:-

  • Mass of the cart (m) = 35 kg
  • Speed (consider Velocity) = 1.2 m/s

To Find: Momentum of the cart.

We know,

p = mv

where,

  • p = Momentum,
  • m = Mass &
  • v = Velocity.

Thus,

p = (35 kg)(1.2 m/s)

→ p = 42 kg m/s (Ans.)

Conclusion:-

A. ☑️ 42 kilogram - metre per second.

6 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
mr Goodwill [35]

Answer:

+17 kg m/s

Explanation:

Question is missing. Found it on google:

"<em>What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg</em>?"

Solution:

we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:

p_i = p_f\\p_b+p_p=p_b'+p_p'

where

p_b = +30 kg m/s is the momentum of the ball before the collision

p_p = 0 is the momentum of the pin before the collision (zero because the pin is stationary)

p_b' = +13 kg m/s is the momentum of the ball after the collision

p_p' is the momentum of the pin after the collision

Solving the equation for p_p', we find:

p_p' = p_b + p_p - p_b' = +30 +0 -(+13)=+17 kg m/s

4 0
4 years ago
You exit the Vet's Office.
kifflom [539]

(1) When you exit the office, your position is 60.8 m and the total distance traveled is 60.8 m.

(2) When you walk to the bank, your position is 60.8 m, displacement is 0 and the total distance traveled is 121.6 m.

(3) When you walk to flower shop, your position is 26.9 m, displacement is 0 and the total distance traveled is 148.5 m.

(4) When you walk to the Vet's Office, your position is 60.8 m, displacement is 60.8 m and the total distance traveled is 182.4 m.

<h3>You exit the Vet's Office</h3>

When you exit the Vet's Office, your position is 60.8 m (assuming your starting position is the bank).

The total distance have you travelled = 26.9 m + 33.9 m = 60.8 m

<h3>You walk to the Bank</h3>

your new position is 60.8 m

your displacement = 60.8 m - 60.8 m = 0 (assuming your starting position is the bank)

total distance have you travelled = 60.8 m +  60.8 m = 121.6 m

<h3>You walk to the Flower Shop</h3>

your new position is 26.9 m

your total displacement = 0 + 26.9 m = 26.9 m

total distance have you travelled = 26.9 m + 121.6 m = 148.5 m

<h3>You walk to the Vet's Office</h3>

your new position is 26.9 m + 33.9 m = 60.8 m

your total displacement = 26.9 m + 33.9 m = 60.8 m

total distance have you travelled = 148.5 m + 33.9 m = 182.4 m

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

5 0
2 years ago
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