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Nimfa-mama [501]
3 years ago
5

Lithium

Physics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:d

Explanation:

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Which statement best explains the relationship between the electric force between two charged objects and the distance between t
spin [16.1K]
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
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4 years ago
If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she
svetlana [45]

Answer:

34.45m

Explanation:

Using the equation of motion formula v² = u²+2as to get the distance travelled

v is the final velocity = 26m/s

u is the initial velocity = 0m/s

a is the acceleration due to gravity = 9.81m/s²

S is the distance travelled

Substituting the given values into the formula;

26² = 0²+2(9.81)s

676 = 0 + 19.62s

19.62s = 676

s = 676/19.62

s = 34.45m

Hence the distance she would travel during the race is 34.45m

7 0
3 years ago
Who was Christa McAuliffe and what happened this year to make her dream come true?
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On July 19th, 1985 Christa McAuliffe was selected as the first teacher to go to space by NASA. Her dream was to be the first teacher to go to space  with all her lessons. Her daughter keeps her dream alive today by setting up 40 schools called the McAuliffe Centre.
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3 years ago
Read 2 more answers
An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then
gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

a=\frac{dv}{dt}=1.76

So, the velocity can be obtained by integrating this expression:

v=1.76t

The velocity is, by definition: v=\frac{dx}{dt}, so

dx=1.76tdt\\x=1.76\frac{t^{2}}{2}.

Do x=11 in order to find the time spent.

11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s

At this time the velocity is: v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}

This velocity remains constant in the section 2, so for that section the movement equation is:

x=v*t\\t=\frac{x}{v}

The left distance is 89 meters, and the velocity is 6.2225\frac{m}{s}, so:

t=\frac{89}{6.2225}=14.303s

So, the total time is 14.303+3.5355s=17.838s

7 0
3 years ago
A 42.2 N force acts at 40* to the ground, causing the object to move a horizontal distance of 8.15 m. How much work was done on
slavikrds [6]

Answer:

W=F.dcos angle

w=42.2 x8.15 x cos40

w=343.93× cos 40

W=343.93 x 0.76

W=261.38 J

7 0
3 years ago
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