Why do FM stations drop out at shorter distances from their source than AM:?

An acorn with a mass of .0300 kg is hanging from a branch in a tree it is 2.50 M off the ground what is the potential energy of

Alekssandra [29.7K]

According to another source this is what I got
0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m )
Hope it helps

5 0

3 years ago

Read 2 more answers

If something is hot, does it contain heat or thermal energy?

zysi [14]

I am absolutely sure that if something is hot, it contain thermal energy only because if a given body is heated its electrons start to move very fast which means that thermal energy is being produced. Hope everything is clear! Regards!

8 0

3 years ago

Calculate the GPE of a rock with a mass of 55kg on a cliff that is 27m high

GaryK [48]

Answer:

P=mgh

P=mghm=55

P=mghm=55g=9.8 or ~10

P=mghm=55g=9.8 or ~10h=27

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

 $kai6417$ 

 #carry on learning

4 0

2 years ago

Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the ma

sladkih [1.3K]

This question is incomplete, the complete question is;

Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.

Answer:

- the magnitude of the resultant force is 557.32 kN

- the direction of resultant force is 48.29°

Explanation:

Given the data in the question and the diagram below,

First we work on the force on the left hand side.

Left Horizontal

$F_{LH$ = βgAr

here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²

we substitute

$F_{LH$ = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N

Left Vertical

$F_{LV$ = ( βgπh² / 2 ) × W

we substitute

$F_{LV$ = [ ( ( 1.6 × 1000 ) × 9.81 × π(1.5)² ) / 2 ] × 6 = 332845.458 N

Now we go to the right hand side

Right Horizontal

$F_{RH$ = βgAh

here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²

we substitute

$F_{RH$ = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N

Right Vertical

$F_{RV$ = ( βgπh² / 4 ) × W

we substitute

$F_{RV$ = [ ( ( 0.8 × 1000 ) × 9.81 × π(1.5)² ) / 4 ] × 6 = 83211.36 N

Hence

Fx = $F_{LH$ - $F_{RH$ = 52974 N - 423792 N = 370818 N

Fy = $F_{LV$ + $F_{RV$ = 332845.458 N + 83211.36 N = 416056.818 N

R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N

R = 557.32 kN

Therefore, the magnitude of the resultant force is 557.32 kN

Direction of resultant force;

tanθ = Fy / Fx

we substitute

tanθ = 416056.818 N / 370818 N

tanθ = 1.121997

θ = tan⁻¹( 1.121997 )

θ = 48.29°

Therefore, the direction of resultant force is 48.29°

4 0

3 years ago

Which is not true of the weak nuclear force?

slavikrds [6]

Answer:

The weak nuclear force is one of the fundamental forces:

Is a force that is responsible of some radiative phenomenoms, like the beta decay.

The intensity is way smaller than the one of the strong interaction, but this is because it acts in a way smaller range. And this can produce atractive and repulsive interactions.

So options D and B can be discarded.

And this force can be repulsive or attractive depending on the phenomena, so the options that are wrong are A and B, because the interaction is both things, not only one.

7 0

3 years ago