Deja enlarged quadrilateral A proportionally.She made each side 4 times as long.

Mathematics

2 answers:

kow [346]3 years ago

6 0

The answer should be that the angles stayed the same.

An example for this would be a right angle. If you double the size of a right angle, the angle itself does not change. The size might, but not the angle itself. It is still going to be a right angle. This is the case with all other angles.

IrinaK [193]3 years ago

4 0

Answer:

16 and stayed the same

Step-by-step explanation:

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From a deck of five cards numbered 2, 4, 6, 8, and 10, respectively, a card is drawn at random and replaced. this is done three

Serga [27]

Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, $2+2+8 = 12$ , and there are no other possibilities, unless you consider the various permutations of the terms.

So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.

Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.

So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of $5 \times 5 \times 5 = 5^3 = 125$ possible triplets.