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3 years ago

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Using a function file, create a function that will compute the area and perimeter of a square given the length of the side. The

input variable will be the length and the output will be the area and the perimeter. Use an input command in the script file to ask the user to enter the length in inches, then use the function to compute the values and in the script file print the values to the screen. Repeat this until the user decides to quit For testing purposes please use the following inputs for the file you submit: Testing Conditions Length 5 in Length 10 in Length 7.5 in

1 answer:

mylen [45]3 years ago

6 0

Answer:

Using Matlab, the code is here

function p = Sq(side)

a = side*side;

p = 4*side;

fprintf("The area of square is %.2f\n",a);

fprintf("The perimeter of square is %.2f\n",p);

end

while true

side = input("Enter the side of square: ");

Sq(side);

c = input("Do you wish to continue (Y/N) ?", 's');

if c=='n' || c=='N'

break;

end

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A hollow steel tube with an inside diameter of 100 mm must carry a tensile load of 400 kN. Determine the outside diameter of the

Olegator [25]

Answer:

119.35 mm

Explanation:

Given:

Inside diameter, d = 100 mm

Tensile load, P = 400 kN

Stress = 120 MPa

let the outside diameter be 'D'

Now,

Stress is given as:

stress = Load × Area

also,

Area of hollow pipe = $\frac{\pi}{4}(D^2-d^2)$

or

Area of hollow pipe = $\frac{\pi}{4}(D^2-100^2)$

thus,

400 × 10³ N = 120 × $\frac{\pi}{4}(D^2-100^2)$

or

D² = tex]\frac{400\times10^3+30\pi\times10^4}{30\pi}[/tex]

or

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7 0

3 years ago

Read 2 more answers

For some transformation having kinetics that obey the Avrami equation , the parameter n is known to have a value of 1.1. If, aft

ivanzaharov [21]

Answer:

total time = 304.21 s

Explanation:

given data

y = 50% = 0.5

n = 1.1

t = 114 s

y = 1 - exp(-kt^n)

solution

first we get here k value by given equation

y = 1 - $e^{(-kt^n)}$ ...........1

put here value and we get

0.5 = 1 - e^{(-k(114)^{1.1})}

solve it we get

k = 0.003786 = 37.86 × $10^{4}$

so here

y = 1 - $e^{(-kt^n)}$

1 - y = $e^{(-kt^n)}$

take ln both side

ln(1-y) = -k × $t^n$

so

t = $\sqrt[n]{-\frac{ln(1-y)}{k}}$ .............2

now we will put the value of y = 87% in equation with k and find out t

t = $\sqrt[1.1]{-\frac{ln(1-0.87)}{37.86*10^{-4}}}$

total time = 304.21 s

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3 years ago

What is the lehr and what purpose does it serve?

levacccp [35]

Explanation:

Step1

Lehr is the long open or closed insulated space for glass manufacturing. Lehr must be large enough to keep the cooling of glass uniform. The function of Lehr is the same as an annealing process in metallurgy.

Step2

Lehr decrease the cooling and temperature variation in glass production. Uneven temperature creates the internal stress in the glass. Lehr reduces the internal stress in the glass product. So, the main purpose of the Lehr is to reduce the internal stress and keep the cooling uniform.

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3 years ago

Wind blows on the side of a fully enclosed hospital located on open flat terrain where V= 120 mi/h. Determine the external press

ss7ja [257]

Answer:

The external pressure is p = -21.9 psf or p = -8.85 psf

Explanation:

Given :

Velocity of wind, v = 120 mi / hr

$k_d = k_c =1$ (wind direction factor)

$k _{zt} = 1$ = topographical factor (for flat terrain)

$q_n$ = velocity pressure at height h

$\therefore q_n = 0.00256 k_z k_{zt} k_d v^2$

$q_n = 0.00256 \times k_z (1)(1)(120)^2$

$= 36.86 k_z$

But for height h = 30 ft, $k_z$ = 0.98 (from table)

$\therefore q_n = 36.86 \times 0.98$

= 36.16

Now, $\frac{L}{B}= \frac{200}{200} =1$ , so $C_p=-0.5$ (from table)

$p = q(G)(C_p)-q_n(GC_{pi})$

where, p = external pressure

G = 0.85 = gust factor (for typical rigid building)

$GC_{pi} = \pm 0.18$ (internal pressure co efficient)

Therefore putting the values,

$p = (36.13)(0.85)(-0.5)-(36.13)(\pm 0.18)$

p = -21.9 psf or p = -8.85 psf

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barxatty [35]

Answer:

Check the explanation

Explanation:

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3 years ago