1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alchen [17]
3 years ago
12

A hollow steel tube with an inside diameter of 100 mm must carry a tensile load of 400 kN. Determine the outside diameter of the

tube if the stress is 120 MPa?
Engineering
2 answers:
Olegator [25]3 years ago
7 0

Answer:

119.35 mm

Explanation:

Given:

Inside diameter, d = 100 mm

Tensile load, P = 400 kN

Stress = 120 MPa

let the outside diameter be 'D'

Now,

Stress is given as:

stress = Load × Area

also,

Area of hollow pipe = \frac{\pi}{4}(D^2-d^2)

or

Area of hollow pipe = \frac{\pi}{4}(D^2-100^2)

thus,

400 × 10³ N = 120 × \frac{\pi}{4}(D^2-100^2)

or

D² = tex]\frac{400\times10^3+30\pi\times10^4}{30\pi}[/tex]

or

D = 119.35 mm

IgorC [24]3 years ago
3 0

Answer:

D =119.35 mm

Explanation:

given data:

inside diameter = 100 mm

load = 400 kN

stress = 120MPa

we know that load is given as

P = \sigma A  

where:

P=400kN = 400000N

\sigma = 120MPa

A =(\frac{1}{4} \pi D^2 - \frac{1}{4}\pi (100^2)

A=\frac{1}{4} \pi (D^2 - 10000)

putting all value in the above equation to get the required diameter value

400 =  120*\frac{1}{4} \pi (D^2 - 10000)

solving for

D =119.35 mm

You might be interested in
When buttons or switches are pressed by humans for arbitrary periods of time, we need to convert a signal level to a pulse. In t
ddd [48]

Answer:

The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.

Explanation:

The code is in the image.

6 0
3 years ago
An aircraft increases its speed by 2% in straight and level flight. If the total lift remains constant determine the revised CL
damaskus [11]

Answer:

96.1%

Explanation:

We know that lift force

F_L=\dfrac{1}{2}C_L\rho AV^2

                                                                    ------------(1)

Where C_L is the lift force coefficient .

          ρ is the density of fluid.

         A is the area.

        V is the velocity.

Now when speed is increased by 2 % and all other parameter remains constant except C_L .

Let;s take new value of lift force coefficient is C_L' .

F_L=\dfrac{1}{2}C_L'\rho A(1.02V)^2

                                                                         -----------(2)

Now from equation 1 and 2

C_L\times V^2=C_L'\times1.0404 V^2

⇒C_L'=0.961C_L

So we can say that revised value of  lift force coefficient is 96.1% of original value.

7 0
3 years ago
The interactive activities in this course
MariettaO [177]

Answer:

A

Explanation:

3 0
3 years ago
The time to failure for a gasket follows the Weibull distribution with ß = 2.0 and a characteristic life of 300 days. What is th
Aleks04 [339]

Answer:

64.11% for 200 days.

t=67.74 days for R=95%.

t=97.2 days for R=90%.

Explanation:

Given that

β=2

Characteristics life(scale parameter α)=300 days

We know that Reliability function for Weibull distribution is given as follows

R(t)=e^{-\left(\dfrac{t}{\alpha}\right)^\beta}

Given that t= 200 days

R(200)=e^{-\left(\dfrac{200}{300}\right)^2}

R(200)=0.6411

So the reliability at 200 days 64.11%.

When R=95 %

0.95=e^{-\left(\dfrac{t}{300}\right)^2}

by solving above equation t=67.74 days

When R=90 %

0.90=e^{-\left(\dfrac{t}{300}\right)^2}

by solving above equation t=97.2 days

7 0
3 years ago
A freezer is maintained at 20°F by removing heat from it at a rate of 75 Btu/min. The power input to the freezer is 0.70 hp, and
Igoryamba

Answer:

Explanation:

Cop of reversible refrigerator = TL / ( TH - TL)

TL = low temperature of freezer = 20 °F

TH = temperature of air around = 75 °F

Heat removal rate QL = 75 Btu/min

W actual, power input = 0.7 hp

conversion on F to kelvin = (T (°F) + 460 ) × 5 / 9

COP ( coefficient of performance) reversible = (20 + 460) × 5/9 / (5/9 ( ( 75 +460) - (20 + 460) ))

COP reversible = 480 / 55 = 8.73

irreversibility expression, I = W actual - W rev

COP r = QL / Wrev

W rev = QL /  COP r  where 75 Btu/min = 1.76856651 hp  where W actual = 0.70 hp

a) W rev =  1.76856651 hp  /  8.73  = 0.20258 hp is reversible power

I = W actual - W rev

b) I = 0.7 hp - 0.20258 hp = 0.4974 hp

c) the second-law efficiency of this freezer = W rev / W actual =  0.20258 hp / 0.7 hp = 0.2894 × 100 = 28.94 %

8 0
3 years ago
Other questions:
  • Water vapor at 6 MPa, 500°C enters a turbine operating at steady state and expands to 20 kPa. The mass flow rate is 3 kg/s, and
    8·1 answer
  • Which pendulum will.mobe faster​
    13·1 answer
  • What is A roofed structure that is similar to a porch, but is detached from the house.
    6·2 answers
  • Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
    13·1 answer
  • Design a posttest-only experiment that would test each of the following causal claims. For each one, identify the study’s indepe
    13·1 answer
  • Which one of the following activities is not exempt from licensure pursuant to Chapter 471, F.S.? A person practicing engineerin
    5·1 answer
  • What is the key to being a good engineer?
    15·2 answers
  • What is the role of the architects in modern development​
    15·1 answer
  • Tech A says that proper footwear may include both leather and steel-toed shoes. Tech B says that when working in the shop, you o
    15·1 answer
  • on the same scale for stress, the tensile true stress-true strain curve is higher than the engineeringstress-engineering strain
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!