Answer:
The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.
Explanation:
The code is in the image.
Answer:
96.1%
Explanation:
We know that lift force

------------(1)
Where
is the lift force coefficient .
ρ is the density of fluid.
A is the area.
V is the velocity.
Now when speed is increased by 2 % and all other parameter remains constant except
.
Let;s take new value of lift force coefficient is
.

-----------(2)
Now from equation 1 and 2
⇒
So we can say that revised value of lift force coefficient is 96.1% of original value.
Answer:
64.11% for 200 days.
t=67.74 days for R=95%.
t=97.2 days for R=90%.
Explanation:
Given that
β=2
Characteristics life(scale parameter α)=300 days
We know that Reliability function for Weibull distribution is given as follows

Given that t= 200 days

R(200)=0.6411
So the reliability at 200 days 64.11%.
When R=95 %

by solving above equation t=67.74 days
When R=90 %

by solving above equation t=97.2 days
Answer:
Explanation:
Cop of reversible refrigerator = TL / ( TH - TL)
TL = low temperature of freezer = 20 °F
TH = temperature of air around = 75 °F
Heat removal rate QL = 75 Btu/min
W actual, power input = 0.7 hp
conversion on F to kelvin = (T (°F) + 460 ) × 5 / 9
COP ( coefficient of performance) reversible = (20 + 460) × 5/9 / (5/9 ( ( 75 +460) - (20 + 460) ))
COP reversible = 480 / 55 = 8.73
irreversibility expression, I = W actual - W rev
COP r = QL / Wrev
W rev = QL / COP r where 75 Btu/min = 1.76856651 hp where W actual = 0.70 hp
a) W rev = 1.76856651 hp / 8.73 = 0.20258 hp is reversible power
I = W actual - W rev
b) I = 0.7 hp - 0.20258 hp = 0.4974 hp
c) the second-law efficiency of this freezer = W rev / W actual = 0.20258 hp / 0.7 hp = 0.2894 × 100 = 28.94 %