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lesya [120]
4 years ago
13

One isotope of lead has 82 protons and 124 neutrons in its nucleus. What is the number of protons in the nucleus of any other is

otope of lead?
Physics
2 answers:
Fantom [35]4 years ago
6 0

every isotope of lead has 82 protons

Kisachek [45]4 years ago
5 0
82, the number of protons are the same;its atomic/proton number is 82.
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As a defensive measure, forces afloat would typically operate in highly dispersed formations, sometimes covering an area of more
hoa [83]

Answer:

B - False

Explanation: a dispersed formation means spreading out, more like an attacking or advancing position. This doesn't depict a defensive measure.

7 0
4 years ago
Are active centers of galaxies that radiate powerful x-rays visible across the universe
ira [324]

Answer:

no

Explanation:

5 0
3 years ago
Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

Separation between the protons, r=3.73\ nm=3.73\times 10^{-9}\ m

Charge on protons, q=1.6\times 10^{-19}\ C

Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
Particles q1, q2, and q3 are in a straight line.
natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0
2 years ago
An Elephant is pulled by a group of clowns across a circus. The elephant has a mass of 1000kg and the clowns are pulling with a
ycow [4]

Answer:

Acceleration = 0.2m/s²

Explanation:

Given the following data;

Mass = 1000kg

Force = 200N

To find acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

Acceleration (a) = \frac{F}{m}

Substituting into the equation;

Acceleration (a) = \frac{200}{1000}

Acceleration = 0.2m/s²

3 0
3 years ago
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