Answer:
You can describe the<u> motion </u>of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its <u> position </u> in relation to another object. The second object acts as a<u> reference</u> point. When an object changes position, you know it has motion. Motion can also be described by finding an object's <u>speed </u>or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called <u>velocity</u>
Explanation:
In the given answer-
<u>Motion</u> is defined as - the change in the movement or position of any object or body.
<u>Position</u> is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.
<u>Reference poin</u>t is a fixed point with regards to which any object or body changes its position. It is also called reference origin.
<u>Speed</u> is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).
<u>Velocity</u> is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).
B) Applied and gravitational forces
Answer:
ΔP = (640 N/cm^2)
Explanation:
Given:-
- The volume increase, ΔV/V0 = 4 ✕ 10^-3
- The Bulk Modulus, B = 1.6*10^9 N/m^2
Find:-
Calculate the force exerted by the moonshine per square centimeter
Solution:-
- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.
B = ΔP / [(ΔV/V)]
- Now rearrange the above relation and solve for ΔP or force per unit area.
ΔP = B* [(ΔV/V)]
- Plug in the values:
ΔP = (1.6*10^9)*(4 ✕ 10^-3)
ΔP = 6400000 N/m^2
- For unit conversion from N/m^2 to N/cm^2 we have:
ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2
ΔP = (640 N/cm^2)
Answer:
The gauge pressure in Pascals inside a honey droplet is 416 Pa
Explanation:
Given;
diameter of the honey droplet, D = 0.1 cm
radius of the honey droplet, R = 0.05 cm = 0.0005 m
surface tension of honey, γ = 0.052 N/m
Apply Laplace's law for a spherical membrane with two surfaces
Gauge pressure = P₁ - P₀ = 2 (2γ / r)
Where;
P₀ is the atmospheric pressure
Gauge pressure = 4γ / r
Gauge pressure = 4 (0.052) / (0.0005)
Gauge pressure = 416 Pa
Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa
Yes you need the light or just go outside to get it from the sun
