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miv72 [106K]
3 years ago
5

Suppose a light source is emitting red light at a wavelength of 700 nm and another light source is emitting ultraviolet light at

a wavelength of 350 nm. Each photon of the ultraviolet light has:________.
a) half the energy of each photon of the red light.
b) twice the energy of each photon of the red light.
c) four times the energy of each photon of the red light.
d) either more or less energy than each photon of the red light, depending on the intensities of the two light sources.
Physics
2 answers:
klasskru [66]3 years ago
7 0

Answer:

b) twice the energy of each photon of the red light.

Explanation:

\lambda = Wavelength

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

Energy of a photon is given by

E=h\nu\\\Rightarrow E=h\dfrac{c}{\lambda}

Let \lambda_1 = 700 nm

\lambda_2=350\\\Rightarrow \lambda_2=\dfrac{\lambda_1}{2}

For red light

E_1=\dfrac{hc}{\lambda_1}

For UV light

E_2=\dfrac{hc}{\dfrac{\lambda_1}{2}}

Dividing the equations

\dfrac{E_1}{E_2}=\dfrac{\dfrac{hc}{\lambda_1}}{\dfrac{hc}{\dfrac{\lambda_1}{2}}}\\\Rightarrow \dfrac{E_1}{E_2}=\dfrac{1}{2}\\\Rightarrow E_2=2E_1

Hence, the answer is  b) twice the energy of each photon of the red light.

d1i1m1o1n [39]3 years ago
7 0

Answer:

b) twice the energy of each photon of the red light.

Explanation:

Given:

wavelength of red light, \lambda_r=7\times 10^{-7}\ m

wavelength of ultraviolet light, \lambda_{uv}=3.5\times 10^{-7}\ m

We know that the energy of a photon is given as:

E=h.\nu ..............(1)

where:

h = plank's constant =6.626\times 10^{-34}\ J.s

\nu=  frequency of the wave

we have the relation:

\nu=\frac{c}{\lambda} ...................(2)

From (1) and (2) we have:

E=\frac{h.c}{\lambda}

<u>Energy of photons for ultraviolet light:</u>

E_{uv}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{3.5\times 10^{-7}}

E_{uv}=5.6794\times 10^{-19}\ J

Since the energy of photons is inversely proportional to the wavelength of the light hence the photon-energy of ultraviolet light is double of the photon-energy of the red light as the wavelength of the red light is twice to that of ultraviolet light.

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An interference pattern is produced by light with a wavelength 580 nm from a distant source incident on two identical parallel s
irakobra [83]

Answer:

Explanation:

1 )

Here

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=580 x 10⁻⁹

distance between slit d = .46 mm

= .46 x 10⁻³

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= λ / d radian

= 580 x 10⁻⁹ / .46 x 10⁻³

= 0.126 x 10⁻² radian

2 )

Angular position of second order interference maxima

2 x  0.126 x 10⁻² radian

= 0.252 x 10⁻² radian

3 )

For intensity distribution the formula is

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For angular position of θ1

δ = .126 x 10⁻² radian

I = I₀ cos².126x 10⁻²/2

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3 years ago
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Nataly_w [17]

Answer:

The option (b) is correct.

Explanation:

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P=\frac{W}{t}

Here, W is the work done, t is the time taken and P is the power.

According to the given problem, six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then determined.

The expression for the equivalent resistance in the series combination is as follows;

R_{eq}=R_{1}+R_{2}......+R_{6}

Put R_{1},R_{2}......,R_{6}=R.

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It is given in the problem that a seventh resistor is added (in series).

R_{eq}=R_{1}+R_{2}......+R_{7}

Put R_{1},R_{2}......,R_{7}=R.

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