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mylen [45]
3 years ago
14

Which statements about Earth’s atmosphere are correct? Check all that apply. helpppp

Physics
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:2,5,6

Explanation:

1) The most abundant gas in atmosphere is Nitrogen .

2) plants make their food from Carbon dioxide in presence of sunlight and give oxygen

3) troposphere is the lowest region of  atmosphere. Chunks of rock from space are burnt in Mesosphere  (50 to 80 km above earth surface)

4) Stratosphere lies 12 to 50 km above earth surface.

5) the troposphere gets colder the higher you go.

6) The ozone in the stratosphere protects us from ultraviolet radiation.

7) troposphere contains nearly 75% of water vapor of atmosphere and it is not constant

In-s [12.5K]3 years ago
5 0

2, 5, and 6 are the correct answers.

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Find the potential energy associated with a 61-kg hiker atop New Hampshire's Mount Washington, 1900 m above sea level. Take the
Natali [406]

Answer:

The potential energy of the hiker is 1.13\times 10^6\ J.

Explanation:

Given that,

Mass of the hiker, m = 61 kg

Height above sea level, h = 1900 m

We need to find the potential energy associated with a 61-kg hiker atop New Hampshire's Mount Washington. The potential energy is given by :

E=mgh

g is the acceleration due to gravity

E=61\ kg\times 9.8\ m/s^2\times 1900\ m\\\\E=1.13\times 10^6\ J

So, the potential energy of the hiker is 1.13\times 10^6\ J. Hence, this is the required solution.

8 0
3 years ago
When will you say a body is in a) uniform acceleration (b) non uniform acceleration
s2008m [1.1K]

Answer:

See below ~

Explanation:

Part (a) :

We can say a body is in uniform acceleration if the acceleration of the object remains constant with respect to time throughout its motion.

Part (b) :

We can say a body is non-uniform acceleration if the acceleration of the body varies with respect to time throughout its motion.

7 0
2 years ago
A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ
Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

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3 years ago
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3 years ago
Principle of quantization of charge​
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3 years ago
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