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4 years ago

Which statements about Earth’s atmosphere are correct? Check all that apply. helpppp

Physics

2 answers:

vagabundo [1.1K]4 years ago

7 0

Answer:2,5,6

Explanation:

1) The most abundant gas in atmosphere is Nitrogen .

2) plants make their food from Carbon dioxide in presence of sunlight and give oxygen

3) troposphere is the lowest region of atmosphere. Chunks of rock from space are burnt in Mesosphere (50 to 80 km above earth surface)

4) Stratosphere lies 12 to 50 km above earth surface.

5) the troposphere gets colder the higher you go.

6) The ozone in the stratosphere protects us from ultraviolet radiation.

7) troposphere contains nearly 75% of water vapor of atmosphere and it is not constant

In-s [12.5K]4 years ago

5 0

2, 5, and 6 are the correct answers.

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. Two identical blocks, each of mass M, are connected by a massless string over a pulley of radius R and moment of inertia I. Th

Dima020 [189]

The angular acceleration of a pulley is described under the equation,

$\theta = (0.5) \alpha t^2$

So things clearing,

$\alpha = \frac{ 2\theta}{t^2}$

b) For point B it is necessary to make a sum of Forces,

$\sum F=0$

In this way,

$Mg - T_1 = Ma$

$T_1 = Mg - Ma$ (1)

For block 2, we have the following relationship,

$T_2 = Ma$ (2)

So,

$T_1 - T_2 = I \frac{a}{R}$ (3)

Substituting (1) and (2) in (3)

$Mg - Ma - Ma = I \frac{a}{R}$

So,

$a = \frac{2\theta R}{t^2}$

**Note that $\alpha R = a$

c) For this point we need to use (1)

$T1 = Mg - Ma = Mg - \frac{M^2\theta R}{t^2}$

using (2)

$RT_2=RT_1-I\alpha$

$T_2= \frac{RM(g-\frac{2\theta R}{t^2})-I\frac{2\theta}{t^2}}{R}$

$T_2=\frac{RMgt^2-2R^2M\theta-2t\theta}{Rt^2}$

5 0

3 years ago

When a cold air mass replaces a warm air mass, it's called a(n) _____ front?

Anvisha [2.4K]

When a cold air mass replaces a warm air mass, this is called a cold front. Some characteristics of a called front before passing are winds coming from south or southwest area, warm temperature, falling pressure, and drizzles. When it passes, the winds are shifting, there is a sudden drop of temperature, minimum pressure followed by a sharp rise. After passing, the winds head to the west or northwest area, temperature is steadily dropping and the pressure is rising steadily.

3 0

3 years ago

Read 2 more answers

Two long, parallel wires are separated by a distance of 2.50 cm. The force per unit length that each wire exerts on the other is

Kisachek [45]

Answer:

The current in the second wire is 8.33 A and the two currents are flowing in the opposite directions

Explanation:

Given that,

The separation between two long parallel wires, d = 2.5 cm

The force per unit length that each wire exerts on the other is, $\dfrac{F}{l}=4\times 10^{-5}\ N/m$

The current in one wire, $I_1=0.6\ A$

(a) The force per unit length of the wire is given by :

$\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}$

On putting all the values we get :

$4\times 10^{-5}=\dfrac{4\pi \times 10^{-7}\times 0.6I_2}{2\pi \times (2.5\times 10^{-2})}$

$I_2=8.33\ A$

So, the current in the second wire is 8.33 A.

(b) It is given that, both the wires repel each other, so the current in other wire is flowing in the opposite direction of the current in the first wire.

Hence, this is the required solution.

6 0

3 years ago

Atmospheric pressure decreases with increment in height. give reason

jekas [21]

Answer:

pressure=height × density×acc due to gravity

pressire is directly proportional to height hence it decreses with decrease in height

here air column height is measured upside down so decreases witn increment

7 0

3 years ago

Read 2 more answers

I NEED HELP BADLY

Marrrta [24]

Answer:

a) Andrea's initial momentum, 200 kg m/s

b) Andrea's final momentum, 0

c) Impulse, = - 200 Ns

d) The force that the seat belt exerts on Andrea, - 400 N

Explanation:

Given data,

The initial velocity of the car is, u = 40 m/s

The mass of Andrea, m = 50 kg

The time period of deceleration, a = 0.5 s

The final velocity of the car, v = 0

a) Andrea's initial momentum,

p = mu

= 50 x 40

= 200 kg m/s

b) Andrea's final momentum

P = mv

= 50 x 0

= 0 kg m/s

c) Impulse

I = mv - mu

= 0 - 200

= - 200 Ns

The negative sign indicated that the momentum is decreased.

d) The force that the seat belt exerts on Andrea

F = (mv - mu)t

= (0 - 200) / 0.5

= - 400 Ns

Hence,the force that the seat belt exerts on Andrea is, - 400 N

7 0

3 years ago