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alexandr402 [8]
3 years ago
15

!!! 100 POINTS !!! PLEASE HELP !!!

Physics
2 answers:
hram777 [196]3 years ago
8 0

Q1. Option 2: basketball


Q2: Newton's first law is <span>the </span>law<span> of inertia. </span>An object at rest stays at rest and an object in motion stays in motion.

<span>
</span>

<span>Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.</span>

<span>
</span>

<span>Q4 Second law says acceleration is dependent upon net force and mass of the object.</span>


Q5. Basketball accelerates when a player tries to dunk it with both hands.


<span>Q6. Third law says f<span>or every action, there is an equal and opposite reaction.</span></span>

<span><span>
</span></span>

<span><span>Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.</span></span>

<span><span>
</span></span>


ivann1987 [24]3 years ago
4 0
The use of newton’s laws applies to the game of soccer. newton’s first law states that and object at rest shall remain at rest or in uniform motion in a straight line unless acted upon by an external force. in this case, the object would be a soccer ball. the ball would be at rest on a field until kicked by a player. newton’s second law states that the net force on an object is equal to the object’s mass x acceleration. this applies to soccer in the form of shooting a goal. the greater the force on the ball, the harder it is for the goalie to save the ball in time. newton’s third law states that all forces in the universe occur in equal but oppositely directed pairs. this can relate to heading the ball. if you don’t hit the ball back with your head once contact is made, the ball will push your head back in the opposite direction, causing a smaller force to be directed onto the ball.






















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550 g of water at 105°C is poured into an 855 g aluminum container with an initial temperature of 11°C. The specific heat of alu
nexus9112 [7]

Answer:

54.22 kJ

Explanation:

In this case, we need to calculate the heat. The expression to use is:

Q = m * C * ΔT

Now, with the specific heat of water (4186 J/ kg K), we can calculate the temperature in which this occurs.

So:

Q = 0.550 * 4186 * (105 - T)

Q = 2302.3 (105 - T)

Q = 241,741.5 - 2302.3T

Now with the Aluminium:

Q = 0.855 * 900 * (T - 11)

Q = 769.5T - 8464.5

Now, with both equations, we solve for the final temperature:

769.5T - 8464.5 = 241,741.5 - 2302.3T

(2302.3 + 769.5)T = 241,741.5 + 8464.5

3071.8T = 250,206

T = 81.45 K

This is the temperature which the change occurs. Now, let's determine the amount of heat from water to Al:

Q = 241,741.5 - 2302.3(81.45)

Q = 54,219.17 J or simply 54.22 kJ.

5 0
3 years ago
f the magnitude of the acceleration of a propeller blade's tip exceeds a certain value amaxamax, the blade tip will fracture. If
Luden [163]

Answer:

The angular velocity is   w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}      

Explanation:

Generally the acceleration experienced by the propeller blade's is broken down into

          The Radial acceleration which is mathematically represented as

                              a_r = \frac{v^2}{r}  = w^2r

And the Tangential  acceleration which is mathematically represented as

                                a_r = \alpha r

  The net acceleration is evaluated as

                      a = \sqrt{a_r^2 + a_t^2}

       

Now since angular speed varies directly with angular acceleration so when acceleration is maximum the angular velocity is maximum also and this point if the propeller blade's tip exceeds it the blade would fracture

                 

So at maximum angular acceleration we a have

             a_{max} = \sqrt{a_r^2 + a_t^2}

                     a_{max}^2 = a_r^2 + a_t^2

                    a_{max}^2 = (w^2r)^2 + (\alpha r)^2

                 a_{max}^2 =  r^2 w^4 + r^2 \alpha ^2

                  a_{max}^2 = r^2 (w^4 + \alpha^2 )

                w^4 +\alpha ^2 = \frac{a_{max}^2}{r^2}

                         w^4 = \frac{a_{max}^2}{r^2}  - \alpha ^2

                         w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}        

                     

3 0
3 years ago
Name the two spectral windows through which electromagnetic radiation easily reaches the surface of earth and describe the large
Anestetic [448]

Answer: • Visible Light, Radio Waves

• Radio - 305-m , at Arecibo, Puerto Rico

Visible Light - 10.4m Mirror, Canary Island

Explanation:

The spectral window is simply the range of frequencies that are correctly measured. It should be noted that the signals that are outside the spectral window are folded when they show up in spectrum.

The two spectral windows through which electromagnetic radiation easily reaches the surface of earth are the visible light and the radio waves.

4 0
3 years ago
Homework help asap!!
ozzi
Where is the picture cant6 see it

7 0
3 years ago
Suppose that the net resistance comes from two resistors in series: R=R1+R2. Assume that you measure each resistor independently
rewona [7]

Answer:

± (.021 ) ohm

Explanation:

In the addition of two physical quantities , the uncertainties are simply added .

So , net uncertainty in the value of R will be

± (.007 +.014)

=± (.021 ) ohm

8 0
3 years ago
Read 2 more answers
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