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alexandr402 [8]
3 years ago
15

!!! 100 POINTS !!! PLEASE HELP !!!

Physics
2 answers:
hram777 [196]3 years ago
8 0

Q1. Option 2: basketball


Q2: Newton's first law is <span>the </span>law<span> of inertia. </span>An object at rest stays at rest and an object in motion stays in motion.

<span>
</span>

<span>Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.</span>

<span>
</span>

<span>Q4 Second law says acceleration is dependent upon net force and mass of the object.</span>


Q5. Basketball accelerates when a player tries to dunk it with both hands.


<span>Q6. Third law says f<span>or every action, there is an equal and opposite reaction.</span></span>

<span><span>
</span></span>

<span><span>Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.</span></span>

<span><span>
</span></span>


ivann1987 [24]3 years ago
4 0
The use of newton’s laws applies to the game of soccer. newton’s first law states that and object at rest shall remain at rest or in uniform motion in a straight line unless acted upon by an external force. in this case, the object would be a soccer ball. the ball would be at rest on a field until kicked by a player. newton’s second law states that the net force on an object is equal to the object’s mass x acceleration. this applies to soccer in the form of shooting a goal. the greater the force on the ball, the harder it is for the goalie to save the ball in time. newton’s third law states that all forces in the universe occur in equal but oppositely directed pairs. this can relate to heading the ball. if you don’t hit the ball back with your head once contact is made, the ball will push your head back in the opposite direction, causing a smaller force to be directed onto the ball.






















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The formulas and procedures that we will use to solve this problem are:

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Where:

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Information about the problem:

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Using the formula of the sphere area we get:

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Applying the pressure formula we get:

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