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alexandr402 [8]
3 years ago
15

!!! 100 POINTS !!! PLEASE HELP !!!

Physics
2 answers:
hram777 [196]3 years ago
8 0

Q1. Option 2: basketball


Q2: Newton's first law is <span>the </span>law<span> of inertia. </span>An object at rest stays at rest and an object in motion stays in motion.

<span>
</span>

<span>Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.</span>

<span>
</span>

<span>Q4 Second law says acceleration is dependent upon net force and mass of the object.</span>


Q5. Basketball accelerates when a player tries to dunk it with both hands.


<span>Q6. Third law says f<span>or every action, there is an equal and opposite reaction.</span></span>

<span><span>
</span></span>

<span><span>Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.</span></span>

<span><span>
</span></span>


ivann1987 [24]3 years ago
4 0
The use of newton’s laws applies to the game of soccer. newton’s first law states that and object at rest shall remain at rest or in uniform motion in a straight line unless acted upon by an external force. in this case, the object would be a soccer ball. the ball would be at rest on a field until kicked by a player. newton’s second law states that the net force on an object is equal to the object’s mass x acceleration. this applies to soccer in the form of shooting a goal. the greater the force on the ball, the harder it is for the goalie to save the ball in time. newton’s third law states that all forces in the universe occur in equal but oppositely directed pairs. this can relate to heading the ball. if you don’t hit the ball back with your head once contact is made, the ball will push your head back in the opposite direction, causing a smaller force to be directed onto the ball.






















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The speed of sound at sea level is normally about 340 m/s. A stationary fire alarm has a frequency of 15,000 Hz. An observer run
Musya8 [376]

Answer:

The velocity of the observer is 6.8 m/s

Explanation:

Doppler effect equation is given by the formula:

f'=\frac{v+v_o}{v-v_s} f\\\\where\ f'\ is \ the\ observed \ frequency=15300\ Hz,v_o\ is\ the\ velocity\ of\ the\ observer,\\v_s\ is\ the\ velocity\ of \ source=0,v\ is\ the\ velocity\ of\ sound=340\ m/s\ and\ f\ is\ actual\\frequency=15000\ Hz.\\\\substituting:\\\\15300=15000(\frac{340+v_o}{340} )\\\\340+v_o=346.8\\\\v_o=6.8\ m/sThe velocity of the observer is 6.8 m/s

3 0
3 years ago
The mass of a hot air ballon including its cargo is 320 kg. the hot air inside it has a density of 1.19 kg/m^3. the density of t
ASHA 777 [7]

Answer:

40454.4 N

Explanation:

mass, m = 320 kg

density of hot air, d = 1.19 kg/m^3

density of cold air, d' = 1.29 kg/m^3

Volume of the balloon, V = mass / density

V = 320 / (1.29 - 1.19)

V = 3200 m^3

So, buoyant force

F = Volume x density outside x gravity

F = 3200 x 1.29 x 9.8

F = 40454.4 N

thus, the buoyant force is 40454.4 N.

3 0
4 years ago
A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If
telo118 [61]

Answer:

  I₂ = 8 mG

Explanation:

The intensity of a beam is

          I = P / A

Where P is the emitted power which is 3) 3

           

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

          I₁ A₁  = I₂  A₂

           I₂ = I₁ A₁ / A₂

The area of ​​the beam if we assume that it is distributed either in the form of a sphere is

           A₁ = 4π r²

We substitute

            I₂ = I₁ (r₁ / r₂)²

           I₂ = 2 (6/3)²

           I₂ = 2 4

           I₂ = 8 mG

3 0
3 years ago
Read 2 more answers
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2
Vaselesa [24]

Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01

7 0
3 years ago
7. Convert 746 days to centuries.
timofeeve [1]

Answer: 0.0208 Centuries

Explanation:

There is 2.739*10^-5 centuries per 1 day.

We can take 746 days and multiply it by that 2.7 number to get how many centuries are in 746 days.

746 *(2.793*10^{-5}) = 0.0208 centuries

4 0
3 years ago
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