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2 years ago

!!! 100 POINTS !!! PLEASE HELP !!!

Physics

2 answers:

hram777 [196]2 years ago

8 0

Q1. Option 2: basketball

Q2: Newton's first law is the law of inertia. An object at rest stays at rest and an object in motion stays in motion.

Q3. A basketball sitting on the floor stays there and a basketball rolling on court keeps on rolling.

Q4 Second law says acceleration is dependent upon net force and mass of the object.

Q5. Basketball accelerates when a player tries to dunk it with both hands.

Q6. Third law says for every action, there is an equal and opposite reaction.

Q7. As a player dribbles, the force the basketball hits the floor with is the same as the force from the floor on the ball. That is why the ball bounces back up in air.

ivann1987 [24]2 years ago

4 0

The use of newton’s laws applies to the game of soccer. newton’s first law states that and object at rest shall remain at rest or in uniform motion in a straight line unless acted upon by an external force. in this case, the object would be a soccer ball. the ball would be at rest on a field until kicked by a player. newton’s second law states that the net force on an object is equal to the object’s mass x acceleration. this applies to soccer in the form of shooting a goal. the greater the force on the ball, the harder it is for the goalie to save the ball in time. newton’s third law states that all forces in the universe occur in equal but oppositely directed pairs. this can relate to heading the ball. if you don’t hit the ball back with your head once contact is made, the ball will push your head back in the opposite direction, causing a smaller force to be directed onto the ball.

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A bird flies 2 km to the south then 0.2 km to the north . What is the displacement of the bird?

lidiya [134]

The displacement of the bird is 1.8 km...because displacement is the distanse of the object from mean position to the travelled position.....hope it helps

8 0

2 years ago

Read 2 more answers

A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What

icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, $F_f$ , acting in the opposite direction (backward)

So the net force acting on the box is

$F_{net}=F-F_f$

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

$F_{net}=ma$

And so

$F-F_f = ma$

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

$a=0$

Therefore we have:

$F-F_f=0$

Which means

$F_f=F$

And since we are told that

$F=25 N$

This means that the force of friction is also 25 N:

$F_f=F=25 N$

6 0

3 years ago

Read 2 more answers

Group of elements with the same number of valence electrons

bekas [8.4K]

Therefore, elements whose atoms can have the same number of valence electrons are grouped together in the periodic table of the elements. As a general rule, a main group element (except hydrogen or helium) tends to react to form a closed shell, corresponding to the electron configuration s2p6.

Hoped I Helped

4 0

2 years ago

The gravitational force of attraction be-

Sliva [168]

Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

$\displaystyle F_g = G \frac{m_1 m_2}{r^2}$

$\displaystyle F_g$ is the gravitational force of attraction

$\displaystyle G$ is the universal gravitational constant

$m_1$ and $m_2$ are the two masses of the two objects

$\displaystyle r$ is the distance between the centers of the two objects.

List the known values:

$\displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}$
$\displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}$
$\displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}$
$\displaystyle r =\ ?$

Plug these values into the equation:

$\displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}$

Notice that the units $\displaystyle \text{N}$ , $\displaystyle \text{kg}^2$ , and $\displaystyle \text{m}$ cancel out. We are left with the unit $\displaystyle \text{m}$ for radius r.