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Goryan [66]
3 years ago
5

What metalloid has commonly been used as an insecticide due to its effectiveness as a poison.

Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

Arsenic.

Explanation:

Hello there!

In this case, since insecticides are substances that act as poisons to get rid of insects in order to prevent their presence and/or reproduction in houses, companies, crops and others, a substance that has been widely used is the metalloid arsenic due to its direct affection of the insect's body (movement, performance, cellular functions).

In addition, high levels of arsenic in food could cause arsenic poisoning in humans as well, that is why such practice must be properly performed and by using the correct security protocol.

Best regards!

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Next to each formula, write the number of atoms of each element found in one unit of the compound
satela [25.4K]
To answer this question I would have to know the elements in the compound
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3 years ago
Test tubes are used mostly for _____. A. storing experimental samples B. making precise measurements of liquids C. containing ex
Annette [7]

Answer: A) Storing experimental samples

Explanation:

It is a common piece of laboratory glassware that can be made of glass or plastic and is opened at the top and closed at the bottom.

It cannot be used for measurements because there is no graduation indicating the volume.

Althought it can contain extra chemicals left over from an experiment, it is not the main proposal of the glassware that is to store samples.

It cannot be used in a microscope and the object for that is a microscope slide.

8 0
3 years ago
One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?
gizmo_the_mogwai [7]
27*9=243 if one mole is equal to 27 grams times that by 9
6 0
2 years ago
Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

Number of moles of gas = 2.00 mol

Temperature = 36°C (36+273= 309K)

Pressure of gas = 1120 torr

Solution:

Formula:

PV = nRT

V = nRT/P

V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr

V = 38563.2 torr • L / 1120 torr

V = 34.43 L

L to mL

34.43 L ×1000 mL / 1 L

34430 mL

5 0
2 years ago
What is the molecular formula of a compound if its emprical formula is NO2 and its molar mass is 138.02 g/mole
Ratling [72]

Answer:

N₃O₆  

Step-by-step explanation:

Data:

EF = NO₂

MM = 138.02 g/mol

Calculations:

EF Mass = (14.01 + 32.00) u

EF Mass = 46.01 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

  n = MF Mass/EF Mass  

  n = 138.02 u/46.01 u  

  n = 3.000 ≈3

MF = (NO₂)₃

MF = N₃O₆

7 0
3 years ago
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