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mina [271]
3 years ago
14

The part of the atom where electrons move is the what

Chemistry
2 answers:
Dominik [7]3 years ago
8 0
Electrons are found in the electron shells of the atom, located at the furthest point from the nucleus.

hope this helps!
marshall27 [118]3 years ago
5 0

Answer:

e

Explanation:

You might be interested in
What type of substance is always made up of a single type if atom
Damm [24]

Answer:

An Element

Explanation:

An Element is made up of only one type of atom (Gold, Silver, etc.)

Hope this helps!

4 0
3 years ago
Butane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix butane and oxygen in the correct
Fittoniya [83]

Answer:

118.776 mmHg

Explanation:

The equation of the reaction is;

C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H20(g)

Now the mole ratio  according to the balanced reaction equation is;

1 : 6.5 : 4 : 5

Hence, the total number of moles present = 1 + 6.5 + 4 + 5 = 16.5 moles

Mole fraction of water vapour = 5/16.5 = 0.303

We also know that;

Partial pressure= mole fraction * total pressure

Partial pressure of H20(g) = 0.303 *  392 mmHg = 118.776 mmHg

7 0
3 years ago
If ammonia were formed from dalton's simplest formula of one atom of each element, what would he have concluded about the relati
baherus [9]
He would have concluded that the order of operations would be different. This therefore would affect the periodic table's order. 
8 0
3 years ago
Someone help please I don’t know the answer to the question I meeed help
mihalych1998 [28]

Answer: 143.3  

137+115+104+263+98 divided by 5.Which gives us 143.3

5 0
3 years ago
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial conc
Anni [7]

Answer:

Ka = 4.76108

Explanation:

  • CO(g) + 2H2(g) ↔ CH3OH(g)

∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

CH3OH(g)          0                0 + x               x = 0.11 M

replacing in Ka:

⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)

⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

⇒ Ka = 4.76108

7 0
3 years ago
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